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-BARSIC- [3]
3 years ago
7

Please help me pls pls pls pls

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

1. B: 47°

2. D: 41°

3. D: 22°

4. D: 80°

5. A: 32°

Step-by-step explanation:

Hope this helps!

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Ms. Hernandez has $100 to spend on parking and admission to the zoo. The parking will cost $7, and admission tickets will cost $
forsale [732]

Answer:

6

Step-by-step explanation:

15.50 x 6= 93 and 100-7=93 therefor its 6

3 0
3 years ago
This graph has rotational symmetry about the points
mart [117]

Answer: Answer for figure one is origin (0,0)

Answer for figure two is (2,4) /

Step-by-step explanation:

a) Here we can see that given graph is the equation of cubic function which is

f(-x) = -f(x) that is given function is odd then rotational symmetry point is origin always ,therefore point of rotational symmetry is origin (0,0)

b) The rotational symmetry of  an ellipse is 180 degrees about the center  of  the ellipse .

And here the center of given ellipse is  (2,4) ,therefore its rotational  symmetry is about (2,4) That is if we rotate the given ellipse 180 degrees about (2,4) it will be at its original position.

7 0
3 years ago
The perimeter of the triangle
Illusion [34]
Area=228 feet sqa.
Length=12 ft.
Breadth=(228/12) ft.
=19 ft.
Perimeter=2(12+19) ft.
=2×31 ft.
=62 ft.

HOPE IT HELPS UH!!☺️☺️
8 0
3 years ago
Given that the measure of ∠x is 60°, and the measure of ∠y is 90°, find the measure of ∠z.
UkoKoshka [18]
The answer is 30 because u need to add 60+90=150 and then subtract 180-150 which gives you 30
7 0
3 years ago
Read 2 more answers
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? {5, 8} {-5, -8} {3, 8} {4, 7} {4, 8}
Savatey [412]
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4

64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7



so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
3 0
3 years ago
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