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STALIN [3.7K]
3 years ago
9

Solve for a. a +(-5) = -12

Mathematics
1 answer:
Verdich [7]3 years ago
5 0
The answer you want is a = -7
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A cone with a diameter of 12 inches has a volume of 640.88 cubic inches. find the height of the cone
BlackZzzverrR [31]

Answer:

The height of the cone is 17\ in

Step-by-step explanation:

we know that

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2}h

In this problem we have

r=12/2=6\ in ----> the radius is half the diameter

V=640.88\ in^{3}

assume \pi=3.14

substitute the values and solve for h

640.88=\frac{1}{3}(3.14)(6)^{2}h

h=640.88*3/((3.14)(36))=17\ in

8 0
3 years ago
Will mark brainliest!! factor the following equation: g(x)=2x²-2x-24​
Darina [25.2K]

Answer:

g(x)=2(x-4)(x+3)​

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Quadrilateral QRST is a square. If the measure of angle RQT is 3x - 6. Find the value of x.
trapecia [35]

Given that quadrilateral QRST is a square.

Each angle of a square is of 90 degrees.

Angle <RQT is also an angle of 90 degrees.

We also given angle RQT = 3x - 6.

So, we can setup an equation as 3x-6 =90.

Now, we need to solve the equation for x.

6 is being subtracted from left side.

We always apply reverse operation. Reverse operation of subtraction is addition.

So, adding 6 on both sides of the equation, we get

3x-6+6 =90+6.

3x = 96.

3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.

So, dividing both sides by 3.

\frac{3x}{3} = \frac{96}{3}

x=32 (final answer).

3 0
3 years ago
How many shapes would I have on term 104?​
pishuonlain [190]

Answer:

313 shapes

Step-by-step explanation:

The nth term is 3n+1

so 3x104=312+1= 313 shapes

4 0
3 years ago
Carrie has 2 meters of ribbon. She cuts off pieces of ribbon that are 5/10 meter, 1/10 meter, and 7/10 meter. How long is the re
vekshin1

Answer:

\frac{7}{10}

Step-by-step explanation:

Carrie has 2 meters of ribbon. She cuts off pieces of ribbon that are 5/10 meter, 1/10 meter, and 7/10 meter

Lets add all the cut of pieces and subtract it from 2 meters

\frac{5}{10} +\frac{1}{10}+\frac{7}{10}=\frac{13}{10}

Now we subtract 13/10 from 2 meters

2 - \frac{13}{10}

To subtract , make the denominator same

\frac{2*10}{1*10} - \frac{13}{10}=\frac{20}{10} - \frac{13}{10}=\frac{7}{10}

7/10 meter is the remaining piece of ribbon

8 0
4 years ago
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