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3 years ago

Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents

Mathematics

1 answer:

insens350 [35]3 years ago

8 0

Answer:

I have seen this problem before very hard.

Step-by-step explanation:

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A vertex of square is at(1,1) and its two parallel sides are y=x and y=x+1. find the equation of the remaining sides.Show your w

belka [17]

Answer:

$\displaystyle y = - x + 2$

$y = - x +1$

Step-by-step explanation:

we are given a vertex of a square i.e (1,1)

and the equations of the two parallel sides

notice that, the given vertex coordinates satisfy one of the parallel side i.e y=x which means that (1,1) points lie on one of Parallel sides

remember that,

every angles of a square is 90°

therefore,

we need to figure out the remaining Perpendicular line of the given Parallel sides so

let's figure out the perpendicular line of y=x line

recall that,

Parallel lines have the same slope thus

$\displaystyle m_{ \rm perpedicular} = - 1$

since we are given a vertex the equation of the perpendicular line should be

$\displaystyle y - 1 = - 1(x - 1)$

distribute:

$\displaystyle y - 1 = - x + 1$

add 1 to both sides:

$\displaystyle y = - x + 2$

to figure out the second perpendicular line we can consider the coordinates (0.5,0.5) of y=x equation

so the slope of the perpendicular line is -1

and the equation:

$y - 0.5 = - 1(x - 0.5)$

distribute:

$y - 0.5 = - x +0 .5$

add 0.5 to both sides:

$y = - x +1$

and we are done!

4 0

3 years ago

An open box is to be made from a rectangular piece of material 9 inches by 12 inches by cutting equal squares from each corner a

grigory [225]

The questions for this problem would be:
1. What is the dimensions of the box that has the maximum volume?
2. What is the maximum volume of the box?

Volume of a rectangular box = length x width x height

From the problem statement,
length = 12 - 2x
width = 9 - 2x
height = x

where x is the height of the box or the side of the equal squares from each corner and turning up the sides

V = (12-2x) (9-2x) (x)
V = (12 - 2x) (9x - 2x^2)
V = 108x - 24x^2 -18x^2 + 4x^3
V = 4x^3 - 42x^2 + 108x

To maximize the volume, we differentiate the expression of the volume and equate it to zero.

V = 4x^3 - 42x^2 + 108x
dV/dx = 12x^2 - 84x + 108
12x^2 - 84x + 108 = 0x^2 - 7x + 9 = 0

Solving for x,
x1 = 5.30 ; Volume = -11.872 (cannot be negative)
x2 = 1.70 ; Volume = 81.872

So, the answers are as follows:

1. What is the dimensions of the box that has the maximum volume?
length = 12 - 2x = 8.60
width = 9 - 2x = 5.60
height = x = 1.70

2. What is the maximum volume of the box?

Volume = 81.872

7 0

3 years ago

Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents​

Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents