Answer:
t = 0 at the start of the projection
Step-by-step explanation:
To solve this we need to find the distance between the 2 positions at any given time, then solve for the least distance
Let t be the time of the 2nd ball, so t + 1 is the time of the first ball
Let g be the gravitational acceleration, v be the horizontal velocity
the y coordinates of the first and 2nd balls


The x coordinates of the 1st and 2nd balls:


The distance between the 2 balls is





As both v and g are constant and cannot be changed, d is minimum when (2t + 1) is minimum, which happens only when t is minimum = 0
Answer:
Start giving more points
Step-by-step explanation:
plus i needed the points
Answer:
-8.85
Step-by-step explanation:
-20 divided by 7
minus 6=-8.85
sry if that make sense
Answer:
The distances between the three pairs of corresponding vertices for each movement must be equal. That is, if you translate points A to A', B to B', et cetera, the distance between A and A', and B and B' are the same.
A translation is a rigid transformation that moves vertices of a figure a fixed distance.
In a general way, a translation moves all points on a shape a fixed distance.