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a_sh-v [17]
3 years ago
11

Solve for x. HELP ON THESE 2 QUESTIONS FASTT !!! PLEASE !!!

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer/Step-by-step explanation:

Recall: the secant-tangent theorem states that when a secant and a tangent drawn from a circle meet at point outside the circle, the product of the external segment of the secant and the length of the secant is equal to the segment length of the tangent.

Thus, we would apply this rule to solve the two problems given.

13. Secant = IK = (x + 0.5)

External segment of secant = 0.5

Tangent segment = IH = 1

Therefore:

0.5*(x + 0.5) = 1²

0.5x + 0.25 = 1

0.5x + 0.25 - 0.25 = 1 - 0.25

0.5x = 0.75

0.5x/0.5 = 0.75/0.5

x = 1.5

14. Secant = JH = (x + 4)

External segment of secant = 4

Tangent segment = JK = 8

Therefore:

4*(x + 4) = 8²

4x + 16 = 64

4x = 64 - 16

4x = 48

4x/4 = 48/4

x = 12

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Answer:

So we already knew all three sides, there are more than one way to do it, for example:

sin∠F = HG/HF = 12/13

cos∠F = GF/HF = 5/13

tan∠F = HG/GF = 12/5

ctg∠F = GF/HG = 5/12

All of them will give you the result which is approximately 67°.

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What is the vertex for this function? y=2x2−12x+16
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Step-by-step explanation:

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3 years ago
What is (8x-30)+6x+(2x+10) simplified?
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(8x-30)+6x+(2x+10)

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The equations of two functions are y =-28x + 8 and y=-29x + 7. Which function is changing more
irinina [24]

<u>Answer:</u>

y=-29x+7 is changing more quickly.

<u>Step-by-step explanation:</u>

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<em>Please mark Brainliest.</em>

4 0
3 years ago
Need help with this question
AleksAgata [21]

First, let's find the slope of the line using the slope formula, which is:

m = \dfrac{y_2 - y_1}{x_2 - x_1}

((x_1, y_1) and (x_2, y_2) are points on the line)


In context of this problem, we can use the formula to find the slope of the line between the two points:

m = \dfrac{-2 -6}{7 - (-1)} = \dfrac{-8}{8} = -1


Now, we can use the slope in the point-slope formula, which will help us find the final equation of the line. (For reference, the point-slope formula is (y - y_1) = m(x - x_1) where (x_1, y_1) is a point on the line)


In the context of the problem, we could use the formula to find the equation of the line:

(y - 6) = -1(x + 1)

(y - 6) = -x - 1

\boxed{y = -x + 5}


The equation of the line is y = -x + 5.

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3 years ago
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