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2 years ago

Which of the equations below has no solution? Due soon need help

Mathematics

2 answers:

Westkost [7]2 years ago

6 0

<h3>Answer: Choice D</h3>

Here's why:

The 4 and 8 on the left side combine to 12. The 5x and -3x on the right hand side combine to 2x.

This means the equation for choice D becomes 2x+12 = 2x-12

From here, subtract 2x from both sides. Doing so will cancel each copy of 2x and the x terms go away entirely. We're left with 12 = -12 which is a false statement since we don't have the same number on both sides. We have a contradiction instead, so there are no solutions here.

No matter what we replace x with in equation D, it will always be false.

If you graphed y = 2x+12 and y = 2x-12, you would find that the lines are parallel. Parallel lines never intersect. Intersection points are solution points, so this is a visual way to see that we don't have any solutions.

Marizza181 [45]2 years ago

3 0

Answer: Pretty sure its B I see non of the same numbers that can fit it.

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3 years ago

How many solutions do 3x+4=3x-5 have

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Answer:

Step-by-step explanation:

Subtract 3x from both sides of the equation:

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