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Shalnov [3]
3 years ago
13

Which of the equations below has no solution? Due soon need help

Mathematics
2 answers:
Westkost [7]3 years ago
6 0
<h3>Answer: Choice D</h3>

Here's why:

The 4 and 8 on the left side combine to 12. The 5x and -3x on the right hand side combine to 2x.

This means the equation for choice D becomes 2x+12 = 2x-12

From here, subtract 2x from both sides. Doing so will cancel each copy of 2x and the x terms go away entirely. We're left with 12 = -12 which is a false statement since we don't have the same number on both sides. We have a contradiction instead, so there are no solutions here.

No matter what we replace x with in equation D, it will always be false.

If you graphed y = 2x+12 and y = 2x-12, you would find that the lines are parallel. Parallel lines never intersect. Intersection points are solution points, so this is a visual way to see that we don't have any solutions.

Marizza181 [45]3 years ago
3 0

Answer:  Pretty sure its B I see non of the same numbers that can fit it.

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\huge \underline{ \boxed{  \sf  Answer}}

Here's the solution ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{ \dfrac{25 {y}^{3} }{ {z}^{2} } }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{ \dfrac{5 \times 5 \times  {y}^{}  \times y \times y}{ {z}^{}  \times z} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{5 \times y}{z}  \times  \sqrt{y}

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