Question

The hoist supports the 125-kg engine. Determine the force the load creates in member DB and in member FB, which contains the hydraulic cylinder H.

Answer 1

Answer:

hello the diagram attached to your question is missing attached below is the missing diagram

answer : Ffb = 1.9381 KN

              Fdb = 2.6 KN

Explanation:

Given data

M = 125-kg

Determine The force on member FB

∅ = tan^-1 ( 3/1) = 71.56°

∑ Me = 0

= 125 * 9.81 * 3 - Ffb sin∅ * 2 = 0

hence : Ffb = 1.9381 KN

also

∑ Ex = 0

Ex = Ffb cos ( 71.56 ) = 1.9381 * cos 71.56 = 0.6132 KN

Determine the Force on member DB

∅ = tan^-1 ( 1/1 ) = 45°

∑ Mc = 0

Ex * 3 = Fdb * sin 45 * 1

Hence Fdb = 2.6 KN

attached below is the free body diagram