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VladimirAG [237]
3 years ago
11

Help please i need to get this done today

Mathematics
1 answer:
Fittoniya [83]3 years ago
5 0

Answer:

( -2, 12)

(-1, 9)

(0, 6)

(1 , 3)

(2, 0)

Step-by-step explanation:

Input the values into the equation

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<img src="https://tex.z-dn.net/?f=Factor%3A%20x%5E2-9" id="TexFormula1" title="Factor: x^2-9" alt="Factor: x^2-9" align="absmidd
Bezzdna [24]

Answer:

x²-9=x²-3²=(x+3)(x-3)

Step-by-step explanation:

use formula

a²-b²=(a+b)(a-b)

7 0
3 years ago
Can anybody please help solving this problem?
pantera1 [17]
Area of the shaded region = Area <span>of a square - Area of a circle
</span>
Side of a square = 2r
Area of a square = (2r)² = 4r²

Area of a circle = πr²

Area of the shaded region = 4r² - πr² = <span>r²(4-π)</span>
7 0
3 years ago
Given: AOB is a right angle
Crazy boy [7]

The missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.

<h3>How to find vertically opposite angles?</h3>

We want to prove that m∠BOC = 90°.

We are given that m∠AOB is a right angle triangle. Thus;

m∠BOC must also be equal to 90°

Now, since m∠BOC and m∠AOB are right angles, then it means that we must equally say that m∠DOA and m∠BOC are vertical opposite angles and they are as such equal.

Thus, the missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.

Read more about vertical opposite angles at; brainly.com/question/24425517

#SPJ1

3 0
1 year ago
Find the area of triangle ABC with the given parts.<br> 3) A = 38.8°<br> b= 13.9 in.<br> c=7.3 in.
tamaranim1 [39]
The area of triangle ABC with the given parts is c- 7.3in
5 0
3 years ago
Find the measure of each exterior angle of a regular polygon in which the sum
Basile [38]
Each exterior angle is 11.25°
8 0
3 years ago
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