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LenaWriter [7]
3 years ago
11

Barney ate 21 M&M's. If he ate 15% of the bag of M&M's, how many were in the bag to start?

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

3.15

i just used the calculater :)

ryzh [129]3 years ago
3 0

Answer:

There were 140 M&M's in the bag to start.

Step-by-step explanation:

Note: The word "of" is a good indicator of multiplication in word problems.

Let's say x is the number of M&M's in the bag. Then,

21=x*15%

Solve for x by dividing by 15% on both sides

140=x

There were 140 M&M's in the bag to start.

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Step-by-step explanation:

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1 year ago
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
Easy math question! brainliest :)
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Answer:

b.) distance north or south of the equator

Step-by-step explanation:

Lines of latitude are horizontal lines parallel with the equator.

The equator is the central line of latitude, and latitude is measured north or south of the equator.

Answer: b.) distance north or south of the equator

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