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Marina CMI [18]
3 years ago
11

Adf;alkjfd;lkaj;ldkfjadfj[klh

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Did you know the moon has moonquakes.

bruh

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What is the total number of digits used when the first 2002 positive even integers are written?
Luda [366]

The total number of digits used when the  first 2002 positive even integers are written is 4 digits

<h3>How to find the number of sequence?</h3>

Using arithmetic sequence,

nth term = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

a = 2

d = 2

nth term = 2 + (2002 - 1)2

nth term = 2 + 4002

nth term = 4004

learn more on sequence here: brainly.com/question/15456604

#SPJ1

7 0
2 years ago
Nine and one half less than four and one half times a number is greater than 62,5. Which of the following represents
morpeh [17]

Answer: (16,O0) That is 16 to positive infinity

Step-by-step explanation:

4.5x - 9.5 > 62.5

4.5x > 62,5 + 9.5

4.5x > 72

x > 72/ 4.5

x> 16

So all real numbers greater than 16 is the solution set.

(16,O0)

I wish I had the infinity symbol on this keyboard!

7 0
3 years ago
Read 2 more answers
Paige has 1 ½ feet of rope for a project. She only needs 2/3 of it. How much rope does she need?
Grace [21]

Answer:

1 foot

Step-by-step explanation:

1 1/2 = 3/2

2/3*3/2 = 1

4 0
3 years ago
Read 2 more answers
Select all that apply.
galina1969 [7]
A and C
^^^^^^^^^^^^^^^
4 0
3 years ago
Read 2 more answers
What is the peremeter of this polygon? (With picture)
lyudmila [28]
Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.


\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -1}}\quad ,&{{ 2}})\quad &#10;%  (c,d)&#10;&({{ 2}}\quad ,&{{ 4}})\\&#10;&({{ 2}}\quad ,&{{ 4}})\quad &#10;%  (c,d)&#10;&({{ 3}}\quad ,&{{ -2}})\\&#10;&({{ 3}}\quad ,&{{ -2}})\quad &#10;%  (c,d)&#10;&({{ -2}}\quad ,&{{ -3}})\\&#10;&({{ -2}}\quad ,&{{ -3}})\quad &#10;%  (c,d)&#10;&({{ -1}}\quad ,&{{ 2}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf -------------------------------\\\\&#10;d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}&#10;\\\\\\&#10;d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\&#10;-------------------------------\\\\&#10;d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\&#10;-------------------------------\\\\&#10;d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}&#10;\\\\\\&#10;d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}

\\\\&#10;-------------------------------\\\\&#10;d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}&#10;\\\\\\&#10;d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}

so, those are their lengths, sum them all up, that's the polygon's perimeter.

4 0
3 years ago
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