He would have 9/12 yards left over because you have to create a common denominator which would be 12. so for 5/6 you would multiply by 2 so you have 10/12. 1/4 you have to multiply by 3 so you get 3/12. and 2/3 you have to multiply by 4 so you get 8/12. then you add them 10/12+3/12+8/12 = 21/12 which simplifies to 1 9/12 and because he used 1 yard he is left with 9/12.
final answer: 9/12 yards
Answer:
The time taken by Allan to complete the marathon 3.5 hours
Step-by-step explanation:
Given as :
The distance cover in marathon = d = 26.2 miles
∵ 1 mile = 1.609 km
So, d = 26.2 × 1.609 km
i.e d = 42.155 kilo meter
The average speed of Allan = s = 12 km per hour
Let the time taken by Allan to complete the marathon = t hours
Now, ∵ Time = 
Or, t = 
Or, t = 
or, t = 3.512 hours
So , The time taken by Allan to complete the marathon = t = 3.5 hours
Hence, The time taken by Allan to complete the marathon 3.5 hours Answer
Hello! I will do my best to help you understand and receive the answers.
Let's begin with our first question..
15.) Dao has 2 3/8 pounds of hamburger meat. He is making 1/4 pound burgers. How many burgers can he make?
For this problem we will have to use division. Our equation (use a calculator if needed) is 2 3/8 divided by 1/4 which equals 3.
Your final answer should be : Dao can make 3 hamburgers total.
I would answer the next question, but I believe from this information above you can try and figure it out. If you are still stuck, message me and i can help you from there.
:))
Answer: option 1.
Explanation:
feasible region is that region which is formed by the lines of constraints.
feasible region is shaded in the attached graph
inequalities becomes equalities to draw the graph
and lines will head towards the origin if constraint satisfied by putting x= 0, y=0
and on the contrary lines will move away from origin when condition of constraint does not satisfied.