Answer:
2a+8 (square root b)................. third option
Well there are 6 units down and 11 units across so 6•11=66. there are 14 red units. 66-14=52. the area of yellow is 52.
Here you go enjoy
Have a good rest of your night
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
Equivalent expressions
A) 
C) 
Step-by-step explanation:
Given expression :
Choices given :
A)
B) 
C)
D) 
To find the equivalent expression.
We will first evaluate the given expression.
⇒ 
[Quotient of a negative dividend and a positive divisor is always negative]
Evaluating each choice to select the equivalents.
A)
⇒ [Quotient of a positive dividend and a negative divisor is always negative]
B)
⇒ 
⇒ 
C)
⇒ 
[Product of a positive and a negative is always a negative]
⇒
D)
⇒ [Product of two negatives is always a positive]
⇒
∴ We see that the choices A and C are equivalent.
