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ycow [4]
3 years ago
15

All of the expressions that have the same value as LaTeX: 892\div8892 ÷ 8. Group of answer choices LaTeX: 8920\div808920 ÷ 80 La

TeX: 894\div10894 ÷ 10 LaTeX: 89.2\div0.0889.2 ÷ 0.08 LaTeX: 8.92\div0.88.92 ÷ 0.8 LaTeX: 0.892\div0.008
Mathematics
1 answer:
algol133 years ago
5 0

Answer:

(a) 8920\div80

(e) 0.892\div0.008

Step-by-step explanation:

Given

892\div8

Required

Select equivalent expression

8920\div80

894\div10

89.2\div0.08

8.92\div0.8

0.892\div0.008

Start  by solving the given expression (using a calculator)

892\div8 = 111.5

Then we solve the given options (using a calculator)

(a) 8920\div80

8920\div80 = 111.5

(b) 894\div10

894\div10 = 89.4

(c) 89.2\div0.08

89.2\div0.08 = 1115

(d) 8.92\div0.8

8.92\div0.8 = 11.15

(e) 0.892\div0.008

0.892\div0.008 = 111.5

The equivalent expressions are (a) and (e)

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3 years ago
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9514 1404 393

Answer:

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  • 2 hundredths of a mile

Step-by-step explanation:

The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.

At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.

Then in 10 minutes, Tyler will run ...

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The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...

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8 0
3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

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3 years ago
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