Answer:
25.0 mol O₂ are required in the second reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
4NH₃ (g) + 5O₂ (g) → 4NO (g) + 6 H₂O(l)
Molar ratio in first reaction is 1:2
For every mol of N₂. I make 2 moles of ammonia. If I have 20 moles of N₂, i'm going to get, 40 moles of ammonia.
In the second reaction, molar ratio between products is 4:5.
If I obtained 40 moles of ammonia in first step, let's prepare the rule of three.
4 moles of ammonia react with 5 moles of O₂
40 moles of ammonia react with ( 40.5) /4 = 25moles
Well protists quite very as organisms i.e it is hard to say if an organism is a protist. Some main features of protists are that they have
1. A membrane enclosed nucleus
2.They are mainly single celled
Also protista are found mainly anywhere water is present for example damp soil, pools and lakes.
Hope this helps :).
<span>Oxidation is the loss of electrons and corresponds to an increase in oxidation state. The reduction is the gain of electrons and corresponds to a decrease in oxidation state. Balancing redox reactions can be more complicated than balancing other types of reactions because both the mass and charge must be balanced. Redox reactions occurring in aqueous solutions can be balanced by using a special procedure called the half-reaction method of balancing. In this procedure, the overall equation is broken down into two half-reactions: one for oxidation and the other for reduction. The half-reactions are balanced individually and then added together so that the number of electrons generated in the oxidation half-reaction is the same as the number of electrons consumed in the reduction half-reaction.</span>
The correct answer is:
a positron is emitted when proton converts to a neutron.
The reaction can be described as following:
₁¹p (proton) → ₀¹n (neutron) + ₁°e (positron or ₁⁰β)
Positron is an antiparticle of a β particle (₋₁°β), which means it has an oposite charge to it, but same mass.
Answer:
Explanation:
yogurt is a colloid because of the milk/dairy in it. yogurt is a complex colloid.