Wouldnt the pressure be the kPa? if so i probably know the answer
Answer:
a) gold - Solid
b) gasoline - liquid
c) oxygen - gaseous
d) olive oil - liquid
e) mercury (found in thermometers) - liquid
f) aluminum - solid
Explanation:
Matter exists in three states viz: solid, gas and liquid. Note that, room temperature is a neither hot or cold temperature, which is about 20-23°C.
A) Gold is a transition metal with the symbol Au. At a room temperature, Gold, like most metals are found as SOLIDS.
B) Gasoline is a liquid mixture of refined hydrocarbons majorly used as fuels.
C) Oxygen is a chemical element with symbol O. It is a constituent of natural air, which is a mixture of different gases including oxygen. Hence, at room temperature, Oxygen is a gas.
D) Olive oil is a vegetable oil got from olives. It is composed of fats and it's a liquid at room temperature.
E) Mercury is an element with symbol Hg. It is the only metallic element found naturally (at room temperature) as a liquid. It is used in thermometers.
F) Aluminum is another chemical element with symbol Al. It is a lustrous metal that occurs as a Solid in room temperature.
The answer is False for sodium bromide it would be NaBr
Answer:
Explanation:
Since we have $N_A$ number of molecules in 22.4 L, in 15 L we have:
$\frac{15}{22.4}\times 6.023 \times 10^{23}$ molecules.
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
