64^x = 16^ x - 1 A: -2 B: -1 C: -1/4 D: -1/3
2 answers:
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Answer:
Step-by-step explanation:
a)
Substitute limits to get
=
Thus converges.
b) 10th partial sum =
=
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)