Answer:
Step-by-step explanation:
STEP 1:
determine equations needed
x= # of $10 tickets
y= # of $14 tickets
QUANTITY EQUATION
x + y= 800
COST EQUATION
$10x + $14y= $9,040
STEP 2:
multiply quantity equation by -14
-14(x + y)= -14(800)
-14x - 14y= -11,200
STEP 3:
add new quantity equation in step 2 to cost equation of step 1 to solve for x using elimination
-14x - 14y= -11,200
10x + 14y= 9040
y term cancels out
-4x= -2160
divide both sides by -4
x= 540 ten dollar tickets
STEP 4:
substitute x value in step 3 into either original equation
x + y= 800
540 + y= 800
subtract 540 from both sides
y= 260 fourteen dollar tickets
ANSWER: There were 540 $10 tickets and 260 $14 tickets sold.
Hope this helps! :)
Answer:
Step-by-step explanation:
How is 2 weeks for quick
The answer is 12 to the question
Hopes this helps you with your question!!
Answer:
no solutions
Step-by-step explanation:
x + 2y = 1
y = − 1/ 2 x + 4
Substitute the second equation into the first
x + 2(-1/2x+4) = 1
Distribute
x -x +8 = 1
Combine like terms
8=1
This is never true so there are no solutions
