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4 years ago

14

Wilson’s theorem says that a number N is prime if and only if (N − 1)! ≡ −1 (mod N). (a) If p is prime, then every number 1 ≤ x

< p is invertible (has an inverse) modulo p. Which of these numbers are their own inverse?

1 answer:

olga2289 [7]4 years ago

6 0

Answer:

The answer to this question can be explained below as:

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What is correct answer to -5-(-8)=

kodGreya [7K]

Answer:

3

Step-by-step explanation:

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3 years ago

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A report issued by the mayor's office states that city residents support building a new baseball

slega [8]

Hey, sorry for the late answer but just in case some one else needs help on the problem here it is.

Answer:

"the sample is biased because it does not represent the population." and "The question is biased toward a Yes response."

Step-by-step explanation:

The sample is biased because they people being surveyed are shopping at a sporting shop so most of them are going to support it.

The question is biased because it says "outdated" and "modern" to try to get people to support it.

I took this quiz and this is correct :) hope I can help some one.

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3 years ago

B = { α , β , γ } Is the following statement True? B 2 ⊆ B 3

Verdich [7]

Answer:

Step-by-step explanation:

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3 years ago

One day, he bought 10 pairs of socks for $2.50 each and 3 pairs of shoes for dollars each. He

IrinaVladis [17]

Answer:

2.50(10) + 3x = 135.97, x = 38.66

Step-by-step explanation:

This should be pretty simple.

Basically, we know that he bought 10 pairs for 2.50 so that's $25 right there.

Our total is 135.97 though-

so here, we take our total from the right side of the equation, and subtract 25 from that.

135.97 - 25 = 115.97

Since he bought three pairs, divide it by 3.

115.97 / 3 = 38.66

One pair of shoes costs $38.66 - hope this helps!

5 0

3 years ago

Given that lim x→1 (5x − 3) = 2, illustrate definition 2 by finding values of δ that correspond to ε = 0.1, ε = 0.05, and ε = 0.

kow [346]

$\displaystyle\lim_{x\to1}(5x-3)=2$

is to say that for any $\varepsilon>0$ , we can find $\delta>0$ such that $0$ implies $|(5x-3)-2|$ .

To that end, we have

$|(5x-3)-2|=|5x-5|=5|x-1|$

which means that if $\varepsilon=0.1$ is given, then we can choose $\delta=\dfrac{0.1}5=0.02$ ; if $\varepsilon=0.05$ , then $\delta=\dfrac{0.05}5=0.01$ ; if $\varepsilon=0.01$ , then $\delta=\dfrac{0.01}5=0.002$ .

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4 years ago