You need to subtract everything to the left side and set it equal to zero. Combine like terms.
Then, the coefficient of x^2 is a, the coefficient of x is b, and the constant term is c.
4x^2 - 5 = 3x + 4
4x^2 - 3x - 5 - 4 = 0
4x^2 - 3x - 9 = 0
a = 4; b = -3; c = -9
Um... I beleive its A due to 2x times 3x with an exponet of 2 would make 6x with the exponet of 2 then you would add 5
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4a + 1v =57
-2a +1v= 9
I will multiply the second by -1 to cancel v variable (elimination method)
4a +1v =57
2a -1v = - 9
add both
6a. = 48
a= 8
4a= 32
32 + v = 57
v= 25
32+25 = 57
-16 +25=9
The total length of the ribbon used is expressed as r and is a product of the number of gifts (g) and the length of ribbon tied in each gift. This relationship may be expressed by the equation,
r = (25) x (g)
