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Brilliant_brown [7]
3 years ago
15

Pls help me answer this question and plsss do not send link

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

x=124.75

Step-by-step explanation:

Sum of angles of a triangle=180°

(x-40)+(x-20)+(1/2- 10)=180°

(x-40)+(x-20)+(−9.5)=180°

x-40+x-20−9.5=180°

x+x-40-20-9.5=180°

2x−69.5=180°

2x=180°+69.5

2x=249.5

2x/2=249.5/2

x=124.75

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How do I do this?<br>*Look at the directions in the photo*​
lora16 [44]

Answer:

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Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
3 years ago
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nadya68 [22]
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3 0
4 years ago
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mr_godi [17]

Answer:

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Step-by-step explanation:

This can be determined as follows

x = the amount of dollars spent at restaurants

y = the amount of dollars spent on groceries

Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have

y = 2x .................. (1)

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We can now solve for x as follows:

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Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:

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Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

7 0
3 years ago
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iren2701 [21]

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6 0
3 years ago
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3 years ago
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