A) y = 2x – 7 and f(x) = 7 – 2xIncorrect. These equations look similar but are not the same. The first has a slope of 2 and a y-intercept of −7. The second function has a slope of −2 and a y-intercept of 7. It slopes in the opposite direction. They do not produce the same graph, so they are not the same function. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5. B) 3x = y – 2 and f(x) = 3x – 2Incorrect. These equations represent two different functions. If you rewrite the first equation in terms of y, you’ll find the equation of the function is y = 3x + 2. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5. C) f(x) = 3x2 + 5 and y = 3x2 + 5Correct. The expressions that follow f(x) = and y = are the same, so these are two different ways to write the same function: f(x) = 3x2 + 5 and y = 3x2 + 5. D) None of the aboveIncorrect. Look at the expressions that follow f(x) = and y =. If the expressions are the same, then the equations represent the same exact function. The correct answer is f(x) = 3x2 + 5 and y = 3x2 + 5.
Answer:
Step-by-step explanation:
- This is a rhombus becuase it a quadralterial and it has four right triangles, and it diagonals bisect each others so it cant be a trapezoid, and paralleolgram. and it doesnt have four right corner angles so it cant be a square or rectangle or kite.
A rhombus inner angle measure is 90 degrees.
So
This means the upper left angle of the top triangle measure is 58 becuase triangle interior theorem.
Since a rhombus bisects angles, angle x measure 58.
Answer:
f⁻¹(x) = (1/2)x +5
Step-by-step explanation:
In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).
... y = 2x -10
... x = 2y -10 . . . . . . swapped variables
... x +10 = 2y . . . . . add 10
... (1/2)x + 5 = y . . . . divide by 2
... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation
Answer:
C
Step-by-step explanation:
bc i’m right
Answer:
Step-by-step explanation:
Let x be the cover page
We are given that a newspaper 's cover page is 
text and photograph fill the rest.
We have to find that how much part of cover's page is the article about endangered species
Text =
Remaining part =
Remaining part =
Therefore, a newspaper;s cover page fill with Photograph =
If the article about endangered species=
of text
Therefore, the article about endangered species=
Hence, the article about endangered species is 
of the cover page.
