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nikdorinn [45]
3 years ago
11

y'all this is due tonight but i dont understand this bc im taking higher math please help im really bad at this

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
Ok so how I get taught to do this is you need to know the basics of algebra if you know that then respond and I’ll tell you how to solve that
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For the first one it’s 9490 & for the second it’s 860
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Please help me in the box below
Fynjy0 [20]
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6 0
3 years ago
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-3x(x+8)+x+2(9-x-x^2) please show solving steps
Flauer [41]

Answer:

-5x^2 - 25x + 18

Step-by-step explanation:

-3x ( x + 8 ) + x + 2 ( 9 - x - x^2 )  ( original equation )

-3x^2 - 24x + x + 18 - 2x - 2x^2   ( distribute )

-3x^2 - 2x^2 - 24x + x - 2x + 18   ( order them based on the variables . )

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Hope its helps !!!

4 0
3 years ago
The population of a town grows at a rate proportional to the population present at time t. The initial population of 500 increas
Mazyrski [523]

Answer:

The population in 40 years will be 1220.

Step-by-step explanation:

The population of a town grows at a rate proportional to the population present at time t.

This means that:

P(t) = P(0)e^{rt}

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The initial population of 500 increases by 25% in 10 years.

This means that P(0) = 500, P(10) = 1.25*500 = 625

We apply this to the equation and find t.

P(t) = P(0)e^{rt}

625 = 500e^{10r}

e^{10r} = \frac{625}{500}

e^{10r} = 1.25

Applying ln to both sides

\ln{e^{10r}} = \ln{1.25}

10r = \ln{1.25}

r = \frac{\ln{1.25}}{10}

r = 0.0223

So

P(t) = 500e^{0.0223t}

What will be the population in 40 years

This is P(40).

P(t) = 500e^{0.0223t}

P(40) = 500e^{0.0223*40} = 1220

The population in 40 years will be 1220.

7 0
4 years ago
What is the 185th digit in the following pattern 12345678910111213141516...?
Natalka [10]
1-9  = 9 digits
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The 185th digit is 7.

4 0
4 years ago
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