Step-by-step explanation:
Applicants can be filled by equal numbers thus 5 applicants can cover per shift
Answer:
17 + 3n
Step-by-step explanation:
20, 23,26 ..............
This is an arithmetic series
First term = a = 20
Common difference = second term - first term
d = 23 - 20 = 3
nth terms = a + (n-1)*d
= 20 + (n -1) *3
= 20 + n*3 - 1*3
= 20 + 3n - 3
= 20 - 3 + 3n
= 17 + 3n
Answer:
Step-by-step explanation:
To solve this, we would follow these simple steps. We have
unvrs :
The arithmetic mean, x-bar for the yellow paper group (Y) = 20.6
The arithmetic mean, x-bar for the green paper group (G) = 21.75
Recall that, H0: µY = µG
And from the data we have, we can see that
H0: µY< µG
We proceed to say that the
T-Test-statistic = -0.404
Also, the p-value: 0.349
From our calculations, we can see that the p-value > 0.05, and as such, we conclude that we will not reject H0. This is because there is not enough evidence to show that test that is printed on the yellow paper decreases anxiety at a 0.05 significance level.
rs + st = rt Plug in the values
3x + 1 + 2x - 2 = 64 Combine like terms (1 and -2)
3x -1 + 2x = 64 Combine like terms (3x and 2x)
-1 + 5x = 64 Add 1 to both sides
5x = 65 Divide both sides by 5
x = 13
The answer is (5x - 4y)(2a + b)
10ax + 5bx - 8ay - 4by = 10ax + 5bx - (8ay + 4by) =<span>
= 5x * 2a + 5x * b - (2a * 4y + b * 4y) =
= 5x(2a + b) - 4y(2a + b) =
= (5x - 4y)(2a + b)</span>