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1 year ago

Write an equation of the line point(2,-1) and parallel passing through y=3x-5 write in slope-intercept form

Mathematics

1 answer:

Tanya [424]1 year ago

3 0

Answer:

y = 3x - 7

Step-by-step explanation:

Since the lines are parallel, the slopes will be the same. In this case 3. Now we have to find the y-intercept. We will use the slope (3), the x (2) and y (-1) to help us do this. We get the x and the y from the ordered pair given(2,-1).

y = mx + b

-1 = 3(2) + b Plug in what you know

-1 = 6 + b Subtract 6 from both sides

-7 = b

Now we can write the equation

y = 3x -7

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Kitty [74]

Answer:

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Step-by-step explanation:

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2 years ago

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Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ

labwork [276]

$(sec x - tan x)^2 \\ \\ = sec^2x - 2 sec x tan x + tan^2 x \\ \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\ \\ =1 - 2 sec x tan x + 2 tan^2 x \\ \\ = 1 - 2tan x(sec x - tan x) \\ \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\ \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\ \\ =1-\frac{2 sin x}{1+sin x}$

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2 years ago

What is the equation of (0,2) and (3,0)

ivolga24 [154]

Let's first find the slope. This is (y_2 - y_1)/(x_2 - x_1), where (x_1, y_1) and (x_2, y_2) are points.

For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.

We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2

The equation of our line is $\boxed{y = -\frac{2}{3}x + 2}$ .

8 0

3 years ago

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Anika [276]

Answer:

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Step-by-step explanation:

it makes sense when u tink about ot

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2 years ago

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melamori03 [73]

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5 0

2 years ago