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Sliva [168]
3 years ago
13

A line has this equation: y = -8x + 8,

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
Parallel lines have the same slope
Y = -8x + 8
The slope will be -8
Therefore: y = -8x + b
Plug in the point
7 = -8(9) + b
7 = -72 + b, b = 79

Solution: y = -8x + 79
You might be interested in
In the figure below, mZ1=(x +48) and m2 2=2xº.<br> Find the angle measures.
NARA [144]
Since m < 1 and m < 2 are complementary angles wherein the measure of their angles add up to 90°, we can establish the following equation:

m < 1 + m < 2 = 90°
x° + 48° + 2x° = 90°

Combine like terms:
48° + 3x° = 90°

Subtract 48° from both sides:

48° - 48° + 3x° = 90° - 48°

3x = 42°

Divide both sides by 3 to solve for x:

3x/3 = 42/3

x = 14°

Plug in the value of x into the equation to fins m< 1 and m < 2:

m < 1 + m < 2 = 90°
(14° + 48°) + 2(14)° = 90°
62° + 28° = 90°

90° = 90° (True statement)

Therefore:

m < 1 = 62°
m < 2 = 28°
6 0
3 years ago
Look at this expression
vladimir2022 [97]

Answer:

OD22264 is the correct answer for that

4 0
3 years ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
What is 4/ 3/5 plz help now I need it
arsen [322]

Answer: 20/3

Step-by-step explanation:

4/1  ÷  3/5

4/1 ÷5/3

= 2-/3

8 0
4 years ago
Read 2 more answers
Help me please I don’t know this stuff
yuradex [85]
Answer: 24 because jeff earned $600 and for jason to earn the same amount 24*25 hours = 600
7 0
3 years ago
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