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oee [108]
3 years ago
10

HELP HELP HELP I REALLY NEED HELP PLEASE PLEASE PLEASE!!!!!

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

i think 7 maybe?

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Question (2)
Viefleur [7K]

Here is the square root spiral

5 0
3 years ago
Read 2 more answers
St. Mary's Church is holding a raffle in which 1172 tickets have been sold at a cost of $2.00 each. Three prizes will be awarded
aleksandrvk [35]

Answer:

Step-by-step explanation:

Given that St. Mary's Church is holding a raffle in which 1172 tickets have been sold at a cost of $2.00 each.

Three prizes will be awarded: 1 for S500;1 for $250; 1 for $125.

Thus total number of tickets = 1172

Of these prize winning are 3

i.e. Tickets        Prize $     Net win amount            Prob       Net win amt*prob

         1                 500                (500-2) =448          1/1172           448/1172

         1                250                 (250-2) =248          1/1172           248/1172

          1               125                   (125-2) =123            1/1172          123/1172

       1169               0                    (0-2) =    -2             1169/1172    -2338/1172

Expected value = Total                                                                 -1519/1172

=-1.296

4 0
3 years ago
Rob is saving up to buy a new MP3 player for every $15 he earns babysitting he saves $6. on Saturday rob earned $90 babysitting
AlekseyPX
To get $90 dollars you multiply $15 • 6. So you would multiply $6 • $6

Answer: $36
8 0
3 years ago
Read 2 more answers
Since opening night, attendance at Play A has increased steadily, while attendance at Play B first rose and then fell. Equations
Y_Kistochka [10]

Answer:

On 5th day and 13th day Attendance was equal for both plays and it was

231 for each .

Step-by-step explanation:

In order to find same attendance ,we need  plug both equation equal

         -x^2+26x+126 = 8x+191

        -x^2+26x-8x+126-191 = 0

        -x^2 +18x-65 =0

      multiplying both sides by -1 ,we get

      x^2 -18x+ 65 =0

        (x-5) (x-13) =0

         x =5 and x =13

On 5th day and 13th  day attendance was same.

And attendance can be obtained by plugging x =5 in either of equation

 y = 8(5)+191

   = 40 +191

  = 231

 

8 0
3 years ago
Suppose a box of Cracker Jacks contains one of 5 toy prizes: a small rubber ball, a whistle, a Captain America decoder ring, a r
lakkis [162]

Answer:

11.42 boxes

Step-by-step explanation:

For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.

After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:

E_2 = (\frac{4}{5})^{-1} = 1.25

For the next unique toy, there is now a 3 in 5 chance of getting it:

E_3 = (\frac{3}{5})^{-1} = 1.67

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

E_4 = (\frac{2}{5})^{-1} = 2.5

Finally, there is a 1 in 5 chance to get the last unique toy:

E_5 = (\frac{1}{5})^{-1} = 5

The expected number of boxes to obtain a full set is:

E=E_1+E_2+E_3+E_4+E_5\\E=1+1.25+1.67+2.5+5\\E=11.42\ boxes

5 0
3 years ago
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