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3 years ago

8

Melinda works at the card shop. She fills the racks with cards. Each rack hold 175 cards. How many cards will Melinda need to fi

ll 5 racks?

2 answers:

tester [92]3 years ago

8 0

Answer:

875

Step-by-step explanation:

175 x 5 =

SVEN [57.7K]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

wtff

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The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 m

bezimeni [28]

Answer: 0.75

Step-by-step explanation:

Given : Interval for uniform distribution : [0 minute, 5 minutes]

The probability density function will be :-

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The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-

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Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75

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3 years ago

There are 6 times as many dogs as cats. If total the total number of dogs and cats is 21, how many dogs are there?

artcher [175]

there are 18 dogs and 3 cats.

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3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in, and a standard deviation given by

kirza4 [7]

Answer: a) The probability is approximately = 0.5793

b) The probability is approximately=0.8810

Step-by-step explanation:

Given : Mean : $\mu= 62.5\text{ in}$

Standard deviation : $\sigma = \text{2.5 in}$

a) The formula for z -score :

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Sample size = 1

For x= 63 in. ,

$z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{1}}}=0.2$

The p-value = $P(z$

$0.5792597\approx0.5793$

Thus, the probability is approximately = 0.5793

b) Sample size = 35

For x= 63 ,

$z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{35}}}\approx1.18$

The p-value = $P(z$

$= 0.8809999\approx0.8810$

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3 years ago

I need help!!<br> I don’t get it!!

Len [333]

Answer:

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Step-by-step explanation:

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3 years ago

A baker cut a pie in half. He cut each half into 3 equal pieces and piece into 2 equal slices. He sold 6 slices. What fraction o

prisoha [69]

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7 0

3 years ago

Read 2 more answers