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tangare [24]
3 years ago
7

A website posts evaluations on airlines. It posts the most positive and the most negative comments for each airline. Discuss the

usefulness of this feedback for a reader wanting to know about the airline.
choose the correct statement below. SELECT ALL THAT APPLY:

A. The reader can accurately assess the airline based on the posted evaluations.

B. the reader cannot accurately assess the airline because the evaluations are not necessarily representative of all evaluations.

C. the reader cannot accurately assess the airline because the method of choosing the sample is unclear.

D. the reader cannot accurately assess the airline without reading all the evaluations. ​
Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

  • B. the reader cannot accurately assess the airline because the evaluations are not necessarily representative of all evaluations.
  • D. the reader cannot accurately assess the airline without reading all the evaluations.

Step-by-step explanation:

Using the most positive and the most negative comments to evaluate the airlines will not be an accurate measure of the airline because these are not a good enough sample. The opinions of those who fall in-between the most positive and negative should also be included as they could have some vital details as well.

Also, in order to be completely accurate, all the comments of the airline should have been posted because this would represent the entire population of comments and so would give the best assessment.

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2/x-5=4x<br><br> What is the value of x
kati45 [8]

Answer:

\large\boxed{x=\dfrac{5\pm3\sqrt3}{2}}

Step-by-step explanation:

Domain:\ x-5\neq0\to x\neq5\\\\\dfrac{2}{x-5}=4x\\\\\dfrac{2}{x-5}=\dfrac{4x}{1}\qquad\text{cross multiply}\\\\(4x)(x-5)=(2)(1)\qquad\text{use the distributive property}\\\\(4x)(x)+(4x)(-5)=2\\\\4x^2-20x=2\\\\2^2x^2-20x=2\\\\(2x)^2-2(2x)(5)=2\qquad\text{add}\ 5^2\ \text{to both sides}\\\\(2x)^2-2(2x)(5)+5^2=2+5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(2x-5)^2=2+25\\\\(2x-5)^2=27\to2x-5=\pm\sqrt{27}\qquad\text{add 5 to both sides}

2x=5\pm\sqrt{9\cdot3}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\2x=5\pm\sqrt9\cdot\sqrt3\\\\2x=5\pm3\sqrt3\qquad\text{divide both sides by 2}\\\\x=\dfrac{5\pm3\sqrt3}{2}

3 0
3 years ago
Jamin wants to paint a wall in his bedroom. In order to know how much paint to buy, he first needs to know the approximate area.
Alekssandra [29.7K]

<u><em>Answer:</em></u>

Area of window = 3 ft²

Area to be painted = 45 ft²

<u><em>Explanation:</em></u>

To get the area to be painted, we will start by getting the area of the whole wall (including the window), then subtract from it the area of the window

<u>1- getting area of whole wall:</u>

From the figure, we can note that the length and width of the wall are given as 6 ft and 8 ft

Area of whole wall = length * width

Area of whole wall = 6 * 8 = 48 ft²

<u>2- getting area of window:</u>

Again, from the figure, we can note that the length and width of the window are 2 ft and 18 in (which is equivalent to 1.5 ft)

Area of window = length * width

Area of window = 2 * 1.5 = 3 ft²

<u>3- getting area to be painted:</u>

Area to be painted = area of whole wall - area of window

Area to be painted = 48 - 3 = 45 ft²

Hope this helps :)

5 0
3 years ago
Simplify.
yulyashka [42]

Answer:

\frac{1}{4}

Step-by-step explanation:

\frac{7}{8} + \frac{-2}{3}= \frac{5}{24}

\frac{5}{24}÷\frac{5}{6}=\frac{30}{120}

\frac{30}{120}=\frac{1}{4}

Please give me Brainlest!

6 0
3 years ago
I NEED HELP IM STUCK ITS CONFUSING,
diamong [38]

Answer:

64

Step-by-step explanation:

88-24=64 which is the right answer

5 0
2 years ago
The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional
jolli1 [7]

Answer:

x=\frac{16}{\sqrt[3]{2}+1 }

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = \frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}

= \frac{I}{x^2}+\frac{2I}{(16-x)^2}

now Q' = 0

⇒I{-\frac{2}{x^3}}+\frac{4}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

[/tex]\frac{1}{x^3} = \frac{2}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

is the required point

5 0
3 years ago
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