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3 years ago

Explain how finding 4 times 384 can help you find 4 times 5,384

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

8 0

5384=5000+384

4 * 5384 = 4(5000+384) = 4 * 5000 + 4 * 384

4 * 5000 = 20000

20000 + 4 * 384

So to find 5384 * 4, you add 20000 to 4*384. Less calculations

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A certain bag of potting soil is 1/4 peat moss, and the rest is dirt, what part is dirt

AVprozaik [17]

If you do the math you'll get 3/4 of the bag is dirt.

4 0

3 years ago

Read 2 more answers

1: What is Abby's total spent on transportation?

stealth61 [152]

Answer:

1. Total spent on transportation $222.2.

2. $ 192.5

3. She spends $30 over the guideline.

Step-by-step explanation:

As per the image attached:

Total monthly spent on transportation = Total monthly car payment + Spent on gas fuel

Total monthly spent on transportation = 120 + 37.9 + 28.4 + 35.9 = $222.2

So, Answer 1. Abby's total spent on transportation = $222.2

Calculating the percentage:

$\Rightarrow \dfrac{\text{Spent on transportation}}{\text{Total monthly income}}$

$\Rightarrow \dfrac{222.2}{1750}\times 100 =12.69\%$

Calculating 11% as per the guideline:

$1750 \times \dfrac{11}{100}\\\Rightarrow \$192.5$

Answer 2. As per the guideline, she should spend $192.5 on transportation.

Difference between spending and guideline = $222.2 - $192.5 = $29.7

Answer 3. She spends $29.7 over the guideline.

8 0

2 years ago

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1

Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

4 0

2 years ago

Solve the inequality for x. –4x + 6 < 50 A) x > –11 B) x > –14 C) x < –11 D) x < –14

Natali [406]

Answer:

x > -11

Step-by-step explanation:

<u>Step 1: Subtract 6 from both sides</u>

-4x + 6 - 6 < 50 - 6

-4x < 44

<u>Step 2: Divide both sides by -4</u>

-4x / -4 < 44 / -4

If you divide by a negative number, you flip the sign.

<em />

Answer: x > -11

6 0

3 years ago

There are 9 students in a class: 7 boys and 2 girls.

Crank

Answer: 9/7

Step-by-step explanation:

6 0

3 years ago