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Arisa [49]
3 years ago
12

A membership to the gym costs $25 per person in 1995. The membership cost has increased by an average of $6 per person for each

year since 1995. Write a linear equation for the cost of a gym membership for one person since 1995.What is the cost of a gym membership in 2009?
Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

The cost of a gym membership would be 109

Step-by-step explanation:

2009-1995=14

thats how many years apart from each other

so its been 14 years $6 for each year so 14x6=84

so the regular price was $25 and went up 84 dollars last 14 years.

25+84=109 so the price of gym membership would be $109

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xz_007 [3.2K]

Answer:

1) 25

2) 2

3) f(g(1)) = 42

Step-by-step explanation:

1) Given that f(x) = 4x^2  + 9

If x = -2

f(-2) = 4(-2)^2 + 9

f(-2) = 4(4) + 9

f(-2) = 16 + 9

f(-2) = 25

2) Given that f(x) = 4x - 6

y = 4x - 6

Replace y  with x

x = 4y - 6

MAke y the subject of the forfmula

4y = x+ 6

y = (x+6)/4

SInce x = 2

f^(-1)(2) = (2+6)/4

f^(-1)(2) = 8/4 = 2

3) If f(x) = 6x and g(x) = x+6

f(g(x)) = f(x+6)

f(x+6) = 6(x+6)

Since x = 1

f(g(1)) = 6(1+6)

f(g(1)) = 6(7)

f(g(1)) = 42

5 0
3 years ago
Miguel and Kat are reading the same book. Miguel reads 5 times as many
n200080 [17]

Answer:

k=\dfrac{m}{5}

Step-by-step explanation:

Let Kat reads k pages of the book.

Miguel reads 5 times as many  pages of the book as Kat. So,

m = 5k ...(1)

Together they read 54 pages. i.e.

m+k = 54 ...(2)

From equation (1),

k=\dfrac{m}5{}

Hence, the equation that can be used to find how many pages Kat read is equal to \dfrac{m}{5}.

6 0
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Step-by-step explanation:

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4 0
3 years ago
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Monica [59]
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4 0
4 years ago
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Katena32 [7]

Answer:

First mechanic worked 20 hours and second mechanic worked 5 hours

Step-by-step explanation:

Let the number of hours the first mechanic worked = a

Let the number of hours the second mechanic worked = b

Therefore, we can write 2 equations and then solve them simultaneously:

a+b=25

65a+90b=1750

Rearranging the first equation: a=25-b

and substituting into the second equation to find b:

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Therefore, first mechanic (a) worked 20 hours and second mechanic (b) worked 5 hours

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