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2 years ago

Helppppppppppppppppp

Mathematics

1 answer:

Elza [17]2 years ago

8 0

Answer:

[text] x = p(m - n) [/tex]

[text] x = pm - pn [/tex]

Step-by-step explanation:

Given:

[text] m = n + \frac{x}{p} [/tex]

Required:

Make x the subject of the formula

Solution:

What we are required to do is to rewrite the equation so that x will be alone on one side while the other variables will be on the other side.

[text] m = n + \frac{x}{p} [/tex]

Subtract n from each side

[text] m - n = n + \frac{x}{p} - n [/tex]

[text] m - n = \frac{x}{p} [/tex]

Multiply both sides by p

[text] p(m - n) = \frac{x}{p}*p [/tex]

[text] p(m - n) = x [/tex]

[text] x = p(m - n) [/tex]

[text] x = pm - pn [/tex]

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Suppose "35" cars start at a car race. In how many ways can the top 3 cars finish the race?

Thepotemich [5.8K]

Answer:

The value is $\left 35 } \atop }} \right. P_3 = 39270$

Step-by-step explanation:

From the question we are told that

The total number of cars is $n = 35$

The number cars considered is $r = 3$

Generally the number of different top three finishes possible for this race of 35 cars is mathematically represented as

$\left n } \atop }} \right. P_r = \frac{n!}{(n - r) !}$

$\left 35 } \atop }} \right. P_3 = \frac{35! }{(35 - 3) !}$

$\left 35 } \atop }} \right. P_3 = \frac{35 * 34 * 33 * 32! }{32 !}$

$\left 35 } \atop }} \right. P_3 = 39270$

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3 years ago

Verify the identity: (1-sinx)/cosx = cosx/(1+sinx)

Lisa [10]

For the answer to the question above,
Let's work with the left-hand side
We're going to times cosx/1-sinx by 1+sinx/1+sinx, you can do this because 1+sinx/1+sinx is equal to 1, so you aren't really changing anything.

After you've times the top and bottom by 1+sinx, you get:

cosx(1+sinx) / (1-sinx)(1+sinx)

The denominator is a difference of squares, so you get 1-sin^2 x

what you have now is

cosx(1+sinx) / 1-sin^2x

You know that 1-sin^2x is equal to cos^2x

so know you have

cosx(1+sinx) / cos^2x

get rid of the cosx on top by simplifying and the cos^2x so that you're left with

(1+sinx) / cos x

Therefore cosx / 1- sinx = 1 + sinx / cos x

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3 years ago

Fred is 58 yes old, and Irene is 18. How many years ago was Fred 5 times as old as Irene. Algebra must be used

Sedaia [141]

So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages $\bf \begin{array}{ccllll}
fred&irene\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
58&18\\
57&17\\
56&16\\
55&15\\
...&...
\end{array}$

notice, Fred is always 40years older than Irene

thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "

now, when is Fred 5 times Irene's age or 5*i or 5i? well,

f = fred's age i = irene's age

f = i + 40
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5i = i + 40 <--- solve for "i" to see how old Irene was then

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3 years ago

Change 3/4 to twelfths

-BARSIC- [3]

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4*3 = 12

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evablogger [386]

Answer:

Try asking again

Step-by-step explanation:

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