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Mathematics

2 answers:

Andrei [34K]2 years ago

7 0

Answer:

3/9 is the answer

hopes this helps brainleist

Step-by-step explanation:

igomit [66]2 years ago

6 0

3/9 because it is the same as 1/3 or 2/6.

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The fishbowl is shaped like a sphere the fishbowl has a diameter of 16 what is the closest value of water in the Fishbowl and cu

katovenus [111]

Answer:

2144.66 cubic inches

Step-by-step explanation:

The fishbowl is shaped like a sphere the fishbowl has a diameter of 16.

What is the closest value of water in the Fishbowl in cubic inches?

From the any question, we were told to find the closest value of the water in the fishbowl in cubic inches.

This means we are to find the volume.

The volume of a sphere is given as:

4/3πr³

We are given Diameter of the fish bowl = 16 inches

Radius = Diameter/2 = 16 inches/2

= 8 inches

Hence,

Volume of the sphere (Volume of water) = 4/3 × π × 8³

= 2144.66 cubic inches

3 0

3 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

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2 years ago

NEED HELP ASAP! WILL MARK BRAINlIEST!

vaieri [72.5K]

Answer: 105 is your sum.

7 0

3 years ago

Read 2 more answers

Write an equation for the description.<br> A number x increased by 12 is 120.

Korvikt [17]

Answer:

x+12=120