Answer:I don’t know I’m in sixth grade
Step-by-step explanation:
Your answer to this problem is 180 girls in green valley elementary school.
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Answer:
Its D Hope it helps
Step-by-step explanation:
Answer:
0.5 or 1/2
Step-by-step explanation:
Step 1. 40/50−15/50
Step 2. 40-25= 25/50
Step 3. 25/50÷ 5 =5/10
5/10÷ 5 =1/2
4/5−3/10=1/2
