Answer:
20%
0.12
Step-by-step explanation:
Convert 1/5 to a percentage.
1/5 * 100% = 20%
Convert 12/100 to a decimal.
0.12
Answer:
28-4x
Step-by-step explanation:
Step 1: Open most inner bracket and simplify
=18-2(x+x-5)
=18-2(2x-5)
Step 2: Expand brackets by multiplying 2 in and simplify
=18-2(2x)-2(-5)
=18-4x+10
=28-4x
Therefore the answer is 28-4x
Answer:
5=3+2
7=5+2
9=7+2
so this is 3,5,7,9
Step-by-step explanation:
x + y = 24 where x and y are the 2 parts of diagonal Other diagonal wil be smaller that 24.
x^2 + z^2 = 13^2
y^2 + z^2 = 20^2 where z = 0.5 * length of smaller diagonal)
form last 2 equations
y^2 - x^2 = 20^2 - 13^2 = 231
now y = 24-x so we have
(24 - x)^2 - x^2 = 231
576 - 48x = 231
48x = 345
x = 7.1875
z^2 = 13^2 - 7.1875^2 = 117.34
z = 1.83
so smaller diagonal = 21.66 cm
looks like its the third choice.
What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M
AURORKA [14]
<h3><u>given</u><u>:</u></h3>
<u>
</u>
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the mode and median of the given numbers set.
<h3><u>solution</u><u>:</u></h3><h3><u>mode</u><u>:</u></h3>
the most frequently occurred number.

<h3><u>median</u><u>:</u></h3>
first arrange all the numbers in either decending or ascending order, then find the number in the middle.


<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>median</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>following</u><u> </u><u>data</u><u> </u><u>set</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>mode</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>and</u><u> </u><u>3</u>