The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)
The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)
Answer: The system of inequalities would produce the region indicated on the graph is Option B
<u>Answer:</u>
355 senior citizen tickets were sold.
<u>Step-by-step explanation:</u>
Assuming a to the the ticket of adults and s to be the ticket of senior citizens, we can write two equations as:
--- (1)
--- (2)
From equation 1, 
.
Substitute 
in equation 2 to get:
Therefore, there were 355 senior citizen tickets sold.
Let x be the number of days.
If Ashley posts 17 status updates each day, then after x days Ashley posts 17x status updates.
If Roberto posts 21 status updates each day, then after x days Roberto posts 21x status updates.
Part A. The combined number of posts for Ashley and Roberto after x days is:
17x+21x.
Part B. The difference between number of posts for Ashley and Roberto after x days is:
21x-17x.
Answer:
The answer is "".
Step-by-step explanation:
Please find the complete question in the attached file.
We select a sample size n from the confidence interval with the mean 
and default 
, then the mean take seriously given as the straight line with a z score given by the confidence interval
Using formula:
The probability that perhaps the mean shells length of the sample is over 4.03 pounds is
Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution
the required probability:
