What Is 1/5 as a percentage
2 answers:
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Answer:
Change in sulfur oxide in the air =
Step-by-step explanation:
Data provided in the question:
Relation between the amount of sulfur oxide in the air and the population as:
S² = 110P² + 20P + 600
Population growth rate, = 10 people per month
Now,
change in sulfur oxide with time i.e
differentiating the given relation with respect to time 't'
we have
=
+ 20
at P = 100 and = 10 people per month
we have
= 2 × 110 × 100 × 10 + 20
or
= 220020
or
=
or
Change in sulfur oxide in the air =
I am assuming you mean 3.0 *10^8 and 1.5 * 10^11.
time = distance/speed right. So,
t = 500 s
time = distance/speed right. So,
t = 500 s