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loris [4]
3 years ago
15

How do I solve this?

Mathematics
1 answer:
Sav [38]3 years ago
8 0
Just plug in a number
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Write an equation in slope-intercept form of<br> the line that passes through (-6,4) and<br> (-1,2).
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Answer:

Step-by-step explanation:

(-6 , 4)  & (-1 , 2)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}

m = -2/5   & (-6 , 4)

y -y1 = m(x -x1)

y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}

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3 years ago
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10 because 45x3=135 205-125=70 70 divided by 7 equals 10
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3 years ago
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Hunter-Best [27]

The absolute value of B is 1 3/5 because although B is in the negatives, absolute value makes it positive.

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3 years ago
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Write a recursive formula for each sequence given or described below.
valentinak56 [21]

Answer:

a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ......

Step-by-step explanation:

Doug has joined a job with a starting salary of $30000 per year.  

Hence, if a₁ is the salary of Doug in the first year, then  

a₁ =30000

Now, each year Doug will receive a raise of $3000 in his salary.

Hence, in the 2nd year, his salary(a₂) will become ( a₁ +3000) per year.

Again, in the 3rd year, his salary(a₃) will become ( a₂ +3000) per year.

Therefor, in the similar manner the recursive formula for his salary in each year will be given as a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ...... {aₙ is the yearly salary of Doug in the nth year} (Answer)

7 0
3 years ago
Solve : 2⁴ <br>I need to show work​
lukranit [14]

Answer:

16

Step-by-step explanation:

2 to the power 4

2 × 2 × 2 × 2 = 4 × 2 × 2 = 8 × 2 = 16

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3 years ago
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