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8_murik_8 [283]
3 years ago
9

Which expression is equivalent to 7x^2-(8x-5)+(5x-3x^2)?

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

your mo- (3x^5 + 8x^3) - (7x^2 - 6x^3) = 3x^5 + 8x^3 - 7x^2 + 6x^3 = 3x^5 + 14x^3 - 7x^2

Step-by-step explanation:

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Write the equation in slope-intercept form of the line that has a slope of -7/8 and contains the point (-4, 9).
lubasha [3.4K]

Answer:

The equation of the line is y = -7/8x + 11/2

Step-by-step explanation:

Since we have the slope and a point to start, we can use point-slope form to find the equation.

y - y1 = m(x - x1)

Use the slope for m and the point at (x1, y1). Then solve for y.

y - 9 = -7/8(x + 4)

y - 9 = -7/8x - 7/2

y = -7/8x + 11/2

6 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
2 years ago
Could you please answer Number 2? This is for geometry
katrin [286]
Answer: 108 degrees

============================================================

Explanation:

Angle ABC is given to be 90 degrees. By the converse of Thales Theorem, we know that AC is a diameter of the circle. 
If we draw a line from A to C, it will pass through the center of the circle.

Therefore, arc AC is 180 degrees as this is half the distance around the circle.

minor arc AD = 72
minor arc CD = x
(minor arc AD) + (minor arc CD) = arc AC
72+x = 180
72+x-72 = 180-72
x = 108

minor arc CD is 108 degrees
7 0
3 years ago
Change the following decimal numbers to percents. .25 .278 2.9 3.0 0.67
umka2103 [35]
25=2,500, 278= 27800%, 2.9=290, 3.0=300, 0.67= 67
3 0
3 years ago
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Genrish500 [490]
What’s the question?
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