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horrorfan [7]
3 years ago
11

If r = 4 and a6 = 192, what is the first term of the sequence?

Mathematics
1 answer:
blagie [28]3 years ago
5 0

Answer:

Answer: Option c. 0.1875 is the first term of the sequence.

Step-by-step explanation:

In this question sixth term of a sequence is given as A(6)= 192

Ratio of terms is given as 4

And we have to calculate the first term of the sequence.

As per formula A(n) = A(1)×r^{n-1}

                         A(6) = A(1)(r)^{6-1}

                          192 = A(1)4^{5}

                           A(1) = \frac{192}{4^{5} }

                                 = 192/1024

                                 =0.1875

So the first term of the sequence will be 0.1875      



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Answer:

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\rm \longrightarrow AB = AM + MB \\  \\  \rm \longrightarrow 33 = (2x - 3) + (5x + 1)  \\  \\  \rm \longrightarrow 2x - 3 + 5x + 1 = 33 \\  \\  \rm \longrightarrow (2x + 5x) + (1 - 3) = 33 \\  \\  \rm \longrightarrow 7x - 2 = 33 \\  \\  \rm \longrightarrow 7x - 2 + 2 = 33 + 2 \\  \\  \rm \longrightarrow 7x = 35 \\  \\  \rm \longrightarrow  \dfrac{7}{7} x =  \dfrac{35}{7}  \\  \\  \rm \longrightarrow x = 5

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