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3 years ago

If r = 4 and a6 = 192, what is the first term of the sequence?

Mathematics

1 answer:

blagie [28]3 years ago

5 0

Answer:

Answer: Option c. 0.1875 is the first term of the sequence.

Step-by-step explanation:

In this question sixth term of a sequence is given as A(6)= 192

Ratio of terms is given as 4

And we have to calculate the first term of the sequence.

As per formula A(n) = A(1)× $r^{n-1}$

A(6) = $A(1)(r)^{6-1}$

192 = $A(1)4^{5}$

A(1) = $\frac{192}{4^{5} }$

= 192/1024

=0.1875

So the first term of the sequence will be 0.1875

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3 years ago

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Answer:

True

Step-by-step explanation:

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$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

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$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

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Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

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