compass.
The idealized ruler, known as a straightedge, is assumed to be infinite in length, have only one edge, and no markings on it. The compass is assumed to have no maximum or minimum radius, and is assumed to "collapse" when lifted from the page, so may not be directly used to transfer distances. (This is an unimportant restriction since, using a multi-step procedure, a distance can be transferred even with collapsing compass; see compass equivalence theorem.) More formally, the only permissible constructions are those granted by Euclid's first three postulates.
It turns out to be the case that every point constructible using straightedge and compass may also be constructed using compass alone.
The ancient Greek mathematicians first conceived straightedge and compass constructions, and a number of ancient problems in plane geometry impose this restriction. The ancient Greeks developed many constructions, but in some cases were unable to do so. Gauss showed that some polygons are constructible but that most are not. Some of the most famous straightedge and compass problems were proven impossible by Pierre Wantzel in 1837, using the mathematical theory of fields.
In spite of existing proofs of impossibility, some persist in trying to solve these problems.[1] Many of these problems are easily solvable provided that other geometric transformations are allowed: for example, doubling the cube is possible using geometric constructions, but not possible using straightedge and compass alone.
In terms of algebra, a length is constructible if and only if it represents a constructible number, and an angle is constructible if and only if its cosine is a constructible number. A number is constructible if and only if it can be written using the four basic arithmetic operations and the extraction of square roots but of no higher-order roots.
Answer:
5
Step-by-step explanation:
Hello!
We know that mike can bind 109 flowers per hour.
Lets create an equation to remember this.
<u>Mikes equation: </u>
<u>109x = y</u>
<u />
<x is representing per hour in this math problem>
We know that John can bind 116 flowers per hour, here is his equation.
<u>Johns equation:</u>
<u>116x = y</u>
<u />
Question: If they work together for 5 hours, how many flowers can they bind?
First, plug in the number five in both equations.
Second, solve the equation by multiplying.
Mikes:
109(5) = y
109 times 5 is 545
y = 545
Johns:
116(5) = y
116 times 5 is 580
y = 580
We want to know how many flowers can they bind if they work together.
This means we need to add the answers of the equations from both mike's and john's together.
545 + 580 = 1,125
The answer is 1,125
john: 56
Mary: 24
(Tbh I'm probably really wrong, I'm so sorry )
