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amid [387]
2 years ago
12

PLS HELP. here's ss in case anyone got confused last time lol

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
4 0
Heyyy....I’m still confused. Nah jk but thx for the points lol
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In 10 years, a bank account with a 5.25% annual interest rate earned $18,375 as simple interest. What was the principal amount?
sdas [7]

Answer:

The principal amont was $35,000

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this problem, we have that:

E = 18375, t = 10, I = 0.0525

We want to find P. So

E = P*I*t

18375 = P*0.0525*10

0.525P = 18375

P = \frac{18375}{0.525}

P = 35000

The principal amont was $35,000

5 0
2 years ago
What is the domain of y= tan(x)?
Anika [276]

Answer:

Step-by-step explanation:

The domain of the function y=tan(x) ) is all real numbers except the values where cos(x) is equal to 0 , that is, the values π2+πn for all integers n . The range of the tangent function is all real numbers.

3 0
3 years ago
A submarine is located 25 meters below sea level it goes up 7 meters then goes down 38 meters wrote plan integer to represent th
uranmaximum [27]
The question is somewhat confusing but assuming you mean where the submarine is after moving up 7 meters then down 38 meters the submarine would now be located 56 meters below sea level
7 0
2 years ago
If a rectangular poster has an area of
d1i1m1o1n [39]
2x ^2 - 9x + 10=\\
2x^2-4x-5x+10=\\
2x(x-2)-5(x-2)=\\
(2x-5)(x-2) \Rightarrow C
8 0
3 years ago
3. 'a' and 'b' are the intercepts made
Julli [10]

Given:

'a' and 'b' are the intercepts made  by a straight-line with the co- ordinate axes.

3a = b and the line  pass through the point (1, 3).

To find:

The equation of the line.

Solution:

The intercept form of a line is

\dfrac{x}{a}+\dfrac{y}{b}=1         ...(i)

where, a is x-intercept and b is y-intercept.

We have, 3a=b.

\dfrac{x}{a}+\dfrac{y}{3a}=1           ...(ii)

The line  pass through the point (1, 3). So, putting x=1 and y=3, we get

\dfrac{1}{a}+\dfrac{3}{3a}=1

\dfrac{1}{a}+\dfrac{1}{a}=1

\dfrac{2}{a}=1

Multiply both sides by a.

2=a

The value of a is 2. So, x-intercept is 2.

Putting a=2 in b=3a, we get

b=3(2)

b=6

The value of b is 6. So, y-intercept is 6.

Putting a=2 and b=6 in (i), we get

\dfrac{x}{2}+\dfrac{y}{6}=1

Therefore, the equation of the required line in intercept form is \dfrac{x}{2}+\dfrac{y}{6}=1.

5 0
2 years ago
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