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2 years ago

Wonder if someone can help me with my math work please

Mathematics

1 answer:

stellarik [79]2 years ago

6 0

Answer:

The slope is negative. The relationship is proportional

Step-by-step explanation:

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Graph the equationX = -2

Vikentia [17]

The answer is a vertical line on the negative -2 (x-axis).

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3 years ago

Eliminate the parameter. x = 1/2t, y = 3t^3 - 1

Elis [28]

X = t/2. t = 2x
y = 3t^3 - 1
y = 3(2x)^3 -1

y = 24x^3 -1

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3 years ago

Hey u all what up u all

Arlecino [84]

Answer:

not too much, you?

Step-by-step explanation:

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3 years ago

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A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak

IgorC [24]

Answer

According to newton law of cooling

$\dfrac{d T}{dt} = k (T - T_a)$

and

$T = Ce^{kt} + T_a$

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

$T(0) = Ce^{0} + T_a$

10 = C + 100

C = -90

now,

$12 = -90e^k + 100$

$e^k = \dfrac{88}{90}$

$k = ln{\dfrac{88}{90}}$

at time equal to t

T(t) = 70

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$70 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{3}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{3})$

t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$98 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{45}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{45})$

t = 390 s

hence, after 390 s the temperature of the body will be 98°C

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2 years ago

Someone please help me find the value of X

Marta_Voda [28]

Answer:

Step-by-step explanation:

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2 years ago