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Simora [160]
2 years ago
5

What numbers are a distance of 2/3 unit from 1/2 on a number line?

Mathematics
1 answer:
Eddi Din [679]2 years ago
4 0

Answer:  1/6

Step-by-step explanation:

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the side is in the shape of a rectangle with an area of 437 square centimeters the length of the rectangle is 19 centimeters wha
miss Akunina [59]
The area of the rectangle is length times width, that is
A = L*W
The problem requires the width so
W = A/L
Given that A = 437 sq. cm and L = 19 cm, therefore
W = 437/19 = 23 cm

That is the answer.
5 0
3 years ago
Which relation is a function? (10 points and Brainliest for a correct answer)
Volgvan
B I’m pretty sure okay bye
7 0
2 years ago
It takes 54 minutes for 4 people to paint 6 walls. How many minuets does it take 6 people to paint 7 walls?
earnstyle [38]

It takes 42 minutes for 6 people to paint 7 walls

<em><u>Solution:</u></em>

It takes 54 minutes for 4 people to paint 6 walls

To find: Minutes required for 6 people to paint 7 walls

If M_1 men can do W_1 work in D_1 days working H_1 hours per day and M_2 men can do W_2 work in D_2 days working H_2 hours per day, then

\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}

M = Number of men

D = Number of days

H = Number of hours per day

W = Amount of work

Here in this sum,

<em><u>54 minutes for 4 people to paint 6 walls</u></em>

H_1 = 54 minutes ; M_1 = 4 people ; W_1 = 6 walls

<em><u>Minutes required for 6 people to paint 7 walls</u></em>

H_2 = ? ; M_2 = 6 people ; W_2 = 7 walls

<em><u>Substituting the values in formula, we get</u></em>

\frac{54 \times 4}{6} = \frac{H_2 \times 6}{7}\\\\9 \times 4 = \frac{H_2 \times 6}{7}\\\\H_2 = \frac{36 \times 7}{6}\\\\H_2 = 42

Thus it takes 42 minutes for 6 people to paint 7 walls

7 0
3 years ago
Use the Distributive Property to write 2(-5+3) as an equivalent expression.
Schach [20]
The correct answer is B: -4
5 0
2 years ago
Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)
andrezito [222]

Answer:

a) \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325

b) The lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

Step-by-step explanation:

a) To simplify the expression \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right) you must:

Apply Difference of Two Squares Formula: \left(a+b\right)\left(a-b\right)=a^2-b^2

a=18,\:b=\tan \left(x\right)

\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)

324-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Apply the Pythagorean Identity 1+\tan ^2\left(x\right)=\sec ^2\left(x\right)

From the Pythagorean Identity, we know that 1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Therefore,

324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325

b) According with the below graph, the lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

3 0
3 years ago
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