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2 years ago

5

What numbers are a distance of 2/3 unit from 1/2 on a number line?

1 answer:

Eddi Din [679]2 years ago

4 0

Answer: 1/6

Step-by-step explanation:

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the side is in the shape of a rectangle with an area of 437 square centimeters the length of the rectangle is 19 centimeters wha

miss Akunina [59]

The area of the rectangle is length times width, that is
A = L*W
The problem requires the width so
W = A/L
Given that A = 437 sq. cm and L = 19 cm, therefore
W = 437/19 = 23 cm

That is the answer.

5 0

3 years ago

Which relation is a function? (10 points and Brainliest for a correct answer)

Volgvan

B I’m pretty sure okay bye

7 0

2 years ago

It takes 54 minutes for 4 people to paint 6 walls. How many minuets does it take 6 people to paint 7 walls?

earnstyle [38]

It takes 42 minutes for 6 people to paint 7 walls

<em><u>Solution:</u></em>

It takes 54 minutes for 4 people to paint 6 walls

To find: Minutes required for 6 people to paint 7 walls

If $M_1$ men can do $W_1$ work in $D_1$ days working $H_1$ hours per day and $M_2$ men can do $W_2$ work in $D_2$ days working $H_2$ hours per day, then

$\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}$

M = Number of men

D = Number of days

H = Number of hours per day

W = Amount of work

Here in this sum,

<em><u>54 minutes for 4 people to paint 6 walls</u></em>

$H_1 = 54 minutes ; M_1 = 4 people ; W_1 = 6 walls$

<em><u>Minutes required for 6 people to paint 7 walls</u></em>

$H_2 = ? ; M_2 = 6 people ; W_2 = 7 walls$

<em><u>Substituting the values in formula, we get</u></em>

$\frac{54 \times 4}{6} = \frac{H_2 \times 6}{7}\\\\9 \times 4 = \frac{H_2 \times 6}{7}\\\\H_2 = \frac{36 \times 7}{6}\\\\H_2 = 42$

Thus it takes 42 minutes for 6 people to paint 7 walls

7 0

3 years ago

Use the Distributive Property to write 2(-5+3) as an equivalent expression.

Schach [20]

The correct answer is B: -4

5 0

2 years ago

Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

3 0

3 years ago