what is the common ratio of a geometric progression were the first term is 3 and the 4th term is 648
1 answer:
Answer:

Step-by-step explanation:
Given
--- First, term
--- Fourth term
Required: Determine the common ratio
The nth term of a GP is

Substitute 4 for n


Substitute 648 and 3 for T4 and 3 respectively.


Take cube roots of both sides
![r =\sqrt[3]{216}](https://tex.z-dn.net/?f=r%20%3D%5Csqrt%5B3%5D%7B216%7D)

<em>The common ratio is 6</em>
You might be interested in
Answer:
ehehe23
Step-by-step explanation:
dgehhegeebsdhsbshshsbe
Lucio can count over the course 30 minute time periods.
Answer:
2 (x+2x)=42
or,6×=42
or x=42/6
or x=7cm
width =x=7cm
length=2x=14cm
Answer:
166.666.667
Hopes this helps
Step-by-step explanation:
The car was going 103 miles per hour.. please mark me brainliest