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MA_775_DIABLO [31]
3 years ago
9

what is the common ratio of a geometric progression were the first term is 3 and the 4th term is 648​

Mathematics
1 answer:
zimovet [89]3 years ago
8 0

Answer:

r = 6

Step-by-step explanation:

Given

a = 3 --- First, term

T_4 = 648 --- Fourth term

Required: Determine the common ratio

The nth term of a GP is

T_n = ar^{n-1

Substitute 4 for n

T_4 = ar^{4-1

T_4 = ar^{3

Substitute 648 and 3 for T4 and 3 respectively.

648 = 3 * r^{3

r^3 = 216

Take cube roots of both sides

r =\sqrt[3]{216}

r = 6

<em>The common ratio is 6</em>

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