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3 years ago

Solve for x. A) 10 C) 11 B) - 7 D) 12

Mathematics

2 answers:

san4es73 [151]3 years ago

8 0

Answer:

i think it is A) 10

Step-by-step explanation:

lidiya [134]3 years ago

6 0

Answer:

D. 12

Step-by-step explanation:

The middle line is two times shorter so:

x - 2 = 2(2x - 19)

simplify

x - 2 = 4x - 38

subtract 4x from both sides

-3x - 2 = -38

add 2 to both sides

-3x = -36

divide both sides by -3

x = 12

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Please help with 15, 17 and 19

Irina-Kira [14]

Given:

15. $\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$

17. $\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$

19. $2^{\log_2100}$

To find:

The values of the given logarithms by using the properties of logarithms.

Solution:

15. We have,

$\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$

Using property of logarithms, we get

$\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)=1$ $[\because \log_aa=1]$

Therefore, the value of $\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$ is 1.

17. We have,

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$

Using properties of logarithms, we get

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-\log_{\frac{3}{4}}\left(\dfrac{3}{4}\right)$ $[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]$

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-1$ $[\because \log_aa=1]$

Therefore, the value of $\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$ is -1.

19. We have,

$2^{\log_2100}$

Using property of logarithms, we get

$2^{\log_2100}=100$ $[\because a^{\log_ax}=x]$

Therefore, the value of $2^{\log_2100}$ is 100.

6 0

3 years ago

1. 40-(-40)+(5x4) i need to know this for my online classes to pass

postnew [5]

Answer:

5x4+80

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the solution to 6x^2 + 2x + 4 = 0?

Angelina_Jolie [31]

Step 1) Divide 6 and 4 (the last 2 numbers) and bring everything else down

6x^24x+2x+4

Step 2) Place in parentheses

(6x^24x)+(2x+4)

Step 3) Figure out what you can take out of each parentheses.

**In the first one, you can take out 6x because both numbers have x and 6 is the largest number 6 and 24 can go into.**

**In the second one, you can only take out 2 because 2 is the largest number that goes into 2 and 4.**

Step 4) You will know you did it correctly when the parentheses match up

6x(x+4) + 2(x+4) <<< this is how it should look

Answer: (6x+2)(x+4)

8 0

3 years ago

Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most

romanna [79]

$4x-7\leq 9$ inequality could be used to find the number of models Walt builds. Correct option B).

Step-by-step explanation:

Here we have , Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most 9 models. We need to find Which inequality could be used to find the number of models Walt builds . Let's find out:

Let the the number Walt builds is x , So Dwight builds 7 fewer models than 4 times the number Walt builds i.e.

⇒ $4x-7$

But , according to question Dwight builds at most 9 models i.e.

⇒ $4x-7\leq 9$

⇒ $4x\leq 16$

⇒ $\frac{4x}{4}\leq \frac{16}{4}$

⇒ $x\leq 4$

Therefore , $4x-7\leq 9$ inequality could be used to find the number of models Walt builds which is Dwight builds at most 9 and Walt builds at most 4 .

4 0

3 years ago

Cos4theta+cos2theta/ cos4theta-cos2theta= _____

vovangra [49]

$\bf \textit{Sum to Product Identities} \\\\ cos(\alpha)+cos(\beta)=2cos\left(\cfrac{\alpha+\beta}{2}\right)cos\left(\cfrac{\alpha-\beta}{2}\right) \\\\\\ cos(\alpha)-cos(\beta)=-2sin\left(\cfrac{\alpha+\beta}{2}\right)sin\left(\cfrac{\alpha-\beta}{2}\right) \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{cos(4\theta )+cos(2\theta )}{cos(4\theta )-cos(2\theta )}\implies \cfrac{2cos\left( \frac{4\theta +2\theta }{2} \right)cos\left( \frac{4\theta -2\theta }{2} \right)}{-2sin\left( \frac{4\theta +2\theta }{2} \right)sin\left( \frac{4\theta -2\theta }{2} \right)} \implies \cfrac{cos\left( \frac{6\theta }{2} \right)cos\left( \frac{2\theta }{2} \right)}{-sin\left( \frac{6\theta }{2} \right)sin\left( \frac{2\theta }{2} \right)}$

$\bf \cfrac{cos(3\theta )cos(\theta )}{-sin(3\theta )sin(\theta )}\implies -\cfrac{cos(3\theta )}{sin(3\theta )}\cdot \cfrac{cos(\theta )}{sin(\theta )}\implies -cot(3\theta )cot(\theta )$

8 0

3 years ago