Question

If x/7=5/3, then x+7/7 is?

Answer 1

Hi there!

$\dfrac{x}{7}$ = $\dfrac{5}{3}$

$3x = 35$

x = $\dfrac{35}{3}$

Now, Substitute th' value of " x " in $\dfrac{x + 7}{7}$ :-


=> $\dfrac{x}{7}$ + $\dfrac{7}{7}$

=> $\dfrac{x}{7}$ + 1

=> $\dfrac{ \dfrac{35}{3} }{7}$ + 1

=> $\dfrac{35}{3}$ × $\dfrac{1}{7}$ + 1

=> $\dfrac{5}{3}$ + 1

=> $\dfrac{5 +3}{3}$

=> $\dfrac{8}{3}$

Hence,
Th' required answer is obtained.

~ Hope it helps!

Answer 2

$\sf Hello!$

$\sf We're\: Given$ :

$\dfrac{\sf x}{\sf 7} = \dfrac{\sf 5}{\sf 3}$

⇒ $\sf 3x = 35$

⇒ $\sf x = \dfrac{\sf 35}{3}$

$\sf Then,$

$\dfrac{\sf x + 7}{\sf 7}$

⇒ $\dfrac{\sf x}{\sf 7} + \dfrac{\sf 7}{\sf 7}$

⇒ $\dfrac{\sf 35}{\sf 3} × \dfrac{\sf 1}{\sf 7} + 1$

⇒ $\dfrac{\sf 5}{\sf 3} + 1$

⇒ $\dfrac{\sf 5 + 3}{\sf 3}$

⇒ $\dfrac{\sf 8}{\sf 3}$

$\sf Therefore,$

$\dfrac{\sf x + 7}{\sf 7}$ = $\dfrac{\sf 8}{\sf 3}$

~ $\sf iCarl$