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Archy [21]
3 years ago
8

For example, Let's say I am graphing a proportional relationship even If it doesn't go through origin and it is an equivalent ra

tios, Is it proportional or does it have to go throught the origin to be proportional?
Mathematics
1 answer:
Lostsunrise [7]3 years ago
6 0

A proportional relationship is described by the equation

... y = k·x

The point (x, y) = (0, 0) is <em>always</em> a solution to this equation.

_____

In short, if the relationship is proportional, its graph will go through the origin. If the graph does not go through the origin, the relationship is not proportional.

___

Note that this is true if the domain includes the origin. You can have y = kx <em>for x > 10 </em>and the graph will <em>not</em> go through the origin because the function is <em>not defined</em> there.

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3. In the equation below, k is a constant. If x = 6, what is the value of k?<br> Vk + 2 - x = 0
ehidna [41]

Answer:

Write the equation with 6 for x

Vk + 2 - 6 = 0

Vk - 4 = 0

Add 4 to both sides

Vk = 4

Divide both sides by V

k = 4/V

Step-by-step explanation:

5 0
3 years ago
Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region​
yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

<u>Concepts:</u>

Area of Square = s²

  • s = side

Area of Triangle = bh/2

  • b = base
  • h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

<u>Solve:</u>

Question # 16

<em>Step One: Find the total area of two squares</em>

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

<em>Step Two: Find the area of the blank triangle</em>

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

<em>Step Three: Subtract the area of the blank triangle from the total area</em>

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

<em>Step One: Find the length of PT</em>

Given:

  • PR = 4 cm
  • RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

<em>Step Two: Find the length of S to PT perpendicularly</em>

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Three: Find the area of ΔPST</em>

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Four: Find the length of Q to PT perpendicularly</em>

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Five: Find the area of ΔPQT</em>

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Six: Combine area of two triangles to find the total area</em>

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

6 0
3 years ago
What is the mode of the set of numbers?<br><br> 2, 2, 3, 4, 4, 5, 7, 7, 7, 10, 16, 17
Ganezh [65]

Answer:

It is 7

Step-by-step explanation:

6 0
3 years ago
I need help ASAP will give brainliest
Tems11 [23]

Answer:

658 + 342 = 1000.

Step-by-step explanation:

Let x be the multiple of 47 and y be the multiple of 19 which gives 1000 while adding.Hence 47x + 19y = 1000On multiplying, find x and yX=14 and y=18So, 47*14= 658 and 19*18= 342 On adding, 658+342=1000Therefore, 658 and 342 are the two parts of 1000.

in simple way

47a + 19b = 1000

a = 14, b = 18

check: 14 x 47 = 658, 18 x 19 = 342, 658 + 342 = 1000.

7 0
3 years ago
Read 2 more answers
Answers now please!​
gulaghasi [49]
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4 0
3 years ago
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