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3 years ago

8

For example, Let's say I am graphing a proportional relationship even If it doesn't go through origin and it is an equivalent ra

tios, Is it proportional or does it have to go throught the origin to be proportional?

1 answer:

Lostsunrise [7]3 years ago

6 0

A proportional relationship is described by the equation

... y = k·x

The point (x, y) = (0, 0) is <em>always</em> a solution to this equation.

_____

In short, if the relationship is proportional, its graph will go through the origin. If the graph does not go through the origin, the relationship is not proportional.

___

Note that this is true if the domain includes the origin. You can have y = kx <em>for x > 10 </em>and the graph will <em>not</em> go through the origin because the function is <em>not defined</em> there.

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Find f(-2) for f(x) = 5•3*x

nirvana33 [79]

Hello!

You put -2 in for x

I don't know whether it is times x or to the power of x so I will do both

5 * 3 * x

5 * 3 * -2 = -30
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5 * 3^x

5 * 3^-2

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stira [4]

Answer:

1) When x is 1, y is 4, and vice versa

2) When x is -6, y is 42, and when x is 7, y is 114

3) When x is -2, y is 2, and when x is 8, y is 42

Step-by-step explanation:

1)

$y=x^2-6x+9$

$y+x=5$ which can be rearranged as $y=5-x$ .

Substituting this lone y into the first equation, you get:

$5-x=x^2-6x+9$

Move everything to one side:

$x^2-5x+4=0$

Factor:

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2)

$y-30=12x$ which can be rearranged as $y=12x+30$ .

$y=x^2+11x-12$

Let's use elimination this time and subtract the first equation from the second:

$0=x^2-x-42$

Factor:

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$x=-6, 7$

$y= -42, 114$

3)

$y=x^2-2x+6$

$y=4x+10$

Let's set the two equations equal to each other through substitution:

$x^2-2x-6=4x+10$

Move everything to one side:

$x^2-6x-16=0$

Factor:

$(x-8)(x+2)=0$

$x=-2, 8$

$y= 2, 42$

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2 years ago

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Answer:

The sum of the interior angles in a triangle is always 180. So, if two angles sum up to 136 degrees, the remaining angle must complement to 180, and it must be

180-136=44

degrees

Step-by-step explanation:

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