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coldgirl [10]
3 years ago
6

What is a Wave In your own words

Physics
1 answer:
Brums [2.3K]3 years ago
6 0
A wave is a big pile of water
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11
GarryVolchara [31]

Explanation:

Given that,

The pilot directs the aircraft to fly due north at 600km/h.

A side-wind blows at  100km/h towards the east.

We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :

v=\sqrt{600^2+100^2} \\\\v=608.27\ m/s

For direction,

\tan\theta=\dfrac{600}{100}\\\\\tan\theta=6\\\\\theta=\tan^{-1}(6)\\\\\theta=80.53^{\circ}

So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.

7 0
3 years ago
Pls help me with this
Ilia_Sergeevich [38]
U is correct on the first one
6 0
3 years ago
A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is
SpyIntel [72]

Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

E = \frac{hc}{\lambda}\\\\

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\

<u>n = 4 x 10¹⁸ photons</u>

8 0
3 years ago
PLS HELP QUICK!!!!!!<br> Make a claim about how light moves through different materials
WINSTONCH [101]

Light, being both a wave and a particle, displays many properties similar to both of them. Light, like waves, travels at different speeds through mediums because they provide any variable amount of resistance. Even air resists light to a degree, and light speed through air is slower than light speed in a vacuum.

6 0
2 years ago
In order for the ball to be able to make a complete circle around the peg, there must be sufficient speed at the top of its arc
Vesna [10]

Answer:

Explanation:

Let T be the tension in the swing

At top point mg-T=\frac{mv^2}{r}

where v=velocity needed to complete circular path

r=distance between point of  rotation to the ball center=L+\frac{d}{2} (d=diameter of ball)

Th-resold velocity is given by mg-0=\frac{mv^2}{r}

To get the velocity at bottom conserve energy at Top and bottom

At top E_T=mg\times 2L+\frac{mv^2}{2}

Energy at Bottom E_b=\frac{mv_0^2}{2}

Comparing two as energy is conserved

v_0^2=4gr+gr

v_0^2=5gr

v_0=\sqrt{5gr}

v_0=\sqrt{5g\left ( \frac{d}{2}+L\right )}

6 0
3 years ago
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