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3 years ago

What happens to the force of attraction between two planets when the masses of both are doubled?

1 answer:

3 0

So as two objects are separated from each other, the force of gravitational attraction between them also decrease. if the separation distance between 2 objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).

Hope this helps :)

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Is a glacier nothing more than a huge mineral flowing downhill?

NNADVOKAT [17]

Yes. A glacier is nothing more than a huge mineral flowing downhill.

4 0

4 years ago

A 9.76-m ladder with a mass of 22.6 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upw

galben [10]

Answer:

Part a)

$\tau_{net} = 1397.1 Nm$

Part b)

$I = 702.06 kg m^2$

Explanation:

Part a)

Torque on the rod is due to two forces

(i) Due to weight of the rod at mid point

(ii) Due to external force applied at the end

Now we have

$\tau_{net} = FL - mg\frac{L}{2}$

$\tau_{net} = 254(9.76) - (22.6)(9.81)(\frac{9.76}{2})$

$\tau_{net} = 1397.1 Nm$

Part b)

As per Newton's law we know that

$\tau = I\alpha$

now we have

$1397.1 Nm = I(1.99 rad/s^2)$

$I = 702.06 kg m^2$

6 0

4 years ago

The current in a hair dryer measures 11 amps. The resistance of the hair dryer is 12 ohms. What is the voltage?

Valentin [98]

Voltage is given by the formula

V = IR (Ohms law)

where V is the Voltage

I is the current

and R is the Resistance

Here it is given that the current is I=11

Resistance is R =12

so plugging this in the formula

V = IR

V= 11 * 12

V= 132 Volts

So the Voltage for the given dryer is 132 Volts

8 0

4 years ago

A hot-water radiator has a surface temperatue of 80 o C and a surface area of 2 m2 . Treating it as a blackbody, find the net ra

faust18 [17]

Answer:

925.04 J/s

Explanation:

T = 80 C = 80 + 273 = 353 K

To = 20 c = 20 + 273 = 293 K

A = 2 m^2

Use the formula for Stefan's law

Energy radiated per second

$E = \sigma A \left ( T^{4}-T_{0}^{4} \right )$

$E = 5.67 \times 10^{-8}\times 2\left ( 353^{4}-293^{4} \right )$

E = 925.04 J/s

3 0

3 years ago

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

Mumz [18]

Answer:

Part a)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Explanation:

Red car

mass = 1000 kg

speed = 10 m/s

Yellow car

mass = 2000 kg

speed = 5 m/s

Blue car

mass = 500 kg

speed = 20 m/s

Light Blue car

mass = 1000 kg

speed = 20 m/s

Green car

mass = 500 kg

speed = 10 m/s

Purple car

mass = 4000 kg

speed = 5 m/s

Part a)

Now we know that momentum of each car is product of mass and velocity

so we will have

Red Car

$P_1 = m v$

$P_1 = (1000)(10)$

$P_1 = 10^4 kg m/s$

Yellow Car

$P_2 = m v$

$P_2 = (2000)(5)$

$P_2 = 10^4 kg m/s$

Blue Car

$P_3 = m v$

$P_3 = (500)(20)$

$P_3 = 10^4 kg m/s$

Light Blue Car

$P_4 = m v$

$P_4 = (1000)(20)$

$P_4 = 2\times 10^4 kg m/s$

Green Car

$P_5 = m v$

$P_5 = (500)(10)$

$P_5 = 5 \times 10^3 kg m/s$

Purple Car

$P_6 = m v$

$P_6 = (4000)(5)$

$P_6 = 2\times 10^4 kg m/s$

So the momentum is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Force is defined as rate of change in momentum

Now let say all cars will stop in same time interval

so we will have

$Force = \frac{impulse}{time}$

so we will have

force is in same order as that of impulse

so it is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

5 0

4 years ago

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