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S_A_V [24]
3 years ago
14

A 240 cm length of string has a mass of 2.5 g. It is stretched with a tension of 8.0 N between fixed supports. (a) What is the w

ave speed for this string? (b) What is the lowest resonant frequency of this string?
Physics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

a.87.6 m/s

b.18.25 Hz

Explanation:

the equation for the wave speed is expressed as

v=\sqrt{\frac{Tl}{m}}\\

where v is the speed,

           T is the tension in Newton

           l is the length

and      m is the mass

Now since

T=8.0N\\m=2.5g=0.0025kg\\l= 240cm=2.40cm\\

by substituting values into the equation, we have

v=\sqrt{\frac{8*2.40}{0.0025} } \\v=87.6m/s\\

b. the expression for the frequency is giving as

Frequency,f=\frac{v}{2l} \\f=\frac{87.6}{2*2.40} \\f=18.25Hz\\.

Note we 2L as the wavelength because we solving for the fundamental frequency as stated in the question.

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Answer: a) 12857.1 m/s/s b) 578.6 N

Explanation:

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Ft = mV2 - mV1

V = AT, 45 / .0035 = 12857.1 m/s/s

(b) .045 x 12857.1 = 578.6 N

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If the pitch of the sound coming out of a speaker increases, which statement is true about the sound wave?
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help me pass the test please there is a couple of questions in my profile to answer i am leaving this one for you to help ​
kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

6 0
2 years ago
D
Rudiy27
Okay so yeah u have to minus then subtract then decide it it’s a method i was taught to do
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Suppose an acorn with a mass of 3.17 g falls off a tree. At a particular moment during the fall, the acorn has a kinetic energy
denis-greek [22]

Potential and kinetic energy both decrease with the acorn's falling potential and kinetic energy.

The acorn's potential energy is at its peak when it reaches the top of the tree, yet its kinetic energy is zero (i.e., it is not accelerating).

The height of the ball reduces along with the potential energy as the acorn tumbles down the tree, but the kinetic energy rises (energy due to motion)

The height will be 0 and the kinetic and potential energy will be zero at the ground. This demonstrates that as an item falls, both potential and kinetic energy are lost.

Learn more about Energy here

brainly.com/question/13881533

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6 0
1 year ago
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