Answer:
(-8,-3)
Step-by-step explanation:
This question is similar to the vertex form of a quadratic equation, so you can think of this equation like f(x) = (x-h)+k. Using this equation, you can determine the vertex (h,k) of |x+8|-3, which is (-8,-3).
These are just a few of the things you will learn in 6th grade. You will learn how to write a two- variable equation, how to identify the graph of an equation, graphing two-variable equations. how to interpret a graph and a word problem, and how to write an equation from a graph using a table, two-dimensional figures,Identify and classify polygons, Measure and classify angles,Estimate angle measurements, Classify triangles, Identify trapezoids, Classify quadrilaterals, Graph triangles and quadrilaterals, Find missing angles in triangles, and a lot more subjects. <span><span><span>Find missing angles in quadrilaterals
</span><span>Sums of angles in polygons
</span><span>Lines, line segments, and rays
</span><span>Name angles
</span><span>Complementary and supplementary angles
</span><span>Transversal of parallel lines
</span><span>Find lengths and measures of bisected line segments and angles
</span><span>Parts of a circle
</span><span>Central angles of circles</span></span>Symmetry and transformations
<span><span>Symmetry
</span><span>Reflection, rotation, and translation
</span><span>Translations: graph the image
</span><span>Reflections: graph the image
</span><span>Rotations: graph the image
</span><span>Similar and congruent figures
</span><span>Find side lengths of similar figures</span></span>Three-dimensional figures
<span><span>Identify polyhedra
</span><span>Which figure is being described
</span><span>Nets of three-dimensional figures
</span><span>Front, side, and top view</span></span>Geometric measurement
<span><span>Perimeter
</span><span>Area of rectangles and squares
</span><span>Area of triangles
</span><span>Area of parallelograms and trapezoids
</span><span>Area of quadrilaterals
</span><span>Area of compound figures
</span><span>Area between two rectangles
</span><span>Area between two triangles
</span><span>Rectangles: relationship between perimeter and area
</span><span>compare area and perimeter of two figures
</span><span>Circles: calculate area, circumference, radius, and diameter
</span><span>Circles: word problems
</span><span>Area between two circles
</span><span>Volume of cubes and rectangular prisms
</span><span>Surface area of cubes and rectangular prisms
</span><span>Volume and surface area of triangular prisms
</span><span>Volume and surface area of cylinders
</span><span>Relate volume and surface area
</span><span>Semicircles: calculate area, perimeter, radius, and diameter
</span><span>Quarter circles: calculate area, perimeter, and radius
</span><span>Area of compound figures with triangles, semicircles, and quarter circles</span></span>Data and graphs
<span><span>Interpret pictographs
</span><span>Create pictographs
</span><span>Interpret line plots
</span><span>Create line plots
</span><span>Create and interpret line plots with fractions
</span><span>Create frequency tables
</span><span>Interpret bar graphs
</span><span>Create bar graphs
</span><span>Interpret double bar graphs</span><span>
</span></span><span>
</span></span>
Answer:
a. 46.35 in ^ 3
b. 15.45 in ^ 3
Step-by-step explanation:
a. To calculate the volume of a cylinder the formula is as follows:
Vc = pi * (r ^ 2) * h
we know the radius because we know the diameter
r = d / 2
diameter is equal to 2.7, therefore the radius is:
r = 2.7 / 2 = 1.35
on the other hand, the height is the diameter of the balls 3 times, since there are 3 of them:
h = 2.7 * 3 = 8.1
replacing, we are left with:
Vc = 3.14 * (1.35 ^ 2) * 8.1 = 46.35 in ^ 3
b. in this case we must calculate the volume of the 3 tennis balls and subtract it from the volume of the can
A sphere has a volume formula:
Vs = 4/3 * pi * r ^ 3
We already know the radius, so we replace:
Vs = 4/3 * 3.14 * 1.35 ^ 3
Vs = 10.30
But how are 3 balls:
10.30 * 3 = 30.90 in ^ 3
we subtract from the can volume:
46.35 - 30.90 = 15.45 in ^ 3 is the area of the empty region
the answer should be 38m+22. hope this helped you!! :)
Answer: 15 and 3 can both be divided by 3 and 1